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How many ways can a committee of three be chosen from a total amount of 4463 students?
Wiki User
∙ 14y ago
The first member chosen can be any one of 4,463 students.
The second member chosen can be any one of the remaining 4,462 students.
The third member chosen can be any one of the remaining 4,461 students.
So there are (4,463 x 4,462 x 4,461) ways to choose three students.
But for every group of three, there are (3 x 2 x 1) = 6 different orders in which the same 3 can be chosen.
So the number of `distinct, unique committees of 3 students is
(4463 x 4462 x 4461) / 6 = 14,805,989,111
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∙ 14y ago
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The first member chosen can be any one of 1,514 students.The second member chosen can be any one of the remaining 1,513 students.The third member chosen can be any one of the remaining 1,512 students.So there are (1,514 x 1,513 x 1,512) ways to choose three students.But for every group of three, there are (3 x 2 x 1) = 6 different orders in which the same 3 can be chosen.So the number of `distinct, unique committees of 3 students is(1514 x 1513 x 1512) / 6 = 577,251,864
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The first member chosen can be any one of 1,514 students.The second member chosen can be any one of the remaining 1,513 students.The third member chosen can be any one of the remaining 1,512 students.So there are (1,514 x 1,513 x 1,512) ways to choose three students.But for every group of three, there are (3 x 2 x 1) = 6 different orders in which the same 3 can be chosen.So the number of `distinct, unique committees of 3 students is(1514 x 1513 x 1512) / 6 = 577,251,864
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