Since there are 4 students, there are 4 possibilities for the 1st place, 3 possibilities for the 2nd place, 2 possibilities for the 3rd place, and 1 possibility for the 4th place. Thus, there are 4*3*2*1 = 24 ways to arrange the 4 students in a row.
(A permutation problem: 4P4 = 4! = 24)
7
raisesiresrises------------------------------------They can be arranged in 5!=120 ways.
9 ways
Six ways.
In 6!, or 720 ways.
7
how many ways can 8 letters be arranged
Five numbers can be arranged in 5! = 120 ways.
720
4! = 24, they can be arranged in 24 different ways
For the first spot, you can choose any one of 5 students. For the second spot, you can choose any one of the remaining 4 students. For the third spot, you can choose any one of the remaining 3 students. etc. So the answer is: 5x4x3x2x1 = 120
In how many distinct ways can the letters of the word MEDDLES be arranged?
They can't be arranged in a million different ways!
raisesiresrises------------------------------------They can be arranged in 5!=120 ways.
10*9*8 = 720
9 ways
It can be arranged in six possible ways.