Since there are 4 students, there are 4 possibilities for the 1st place, 3 possibilities for the 2nd place, 2 possibilities for the 3rd place, and 1 possibility for the 4th place. Thus, there are 4*3*2*1 = 24 ways to arrange the 4 students in a row.
(A permutation problem: 4P4 = 4! = 24)
7
raisesiresrises------------------------------------They can be arranged in 5!=120 ways.
9 ways
Six ways.
In 6!, or 720 ways.
7
how many ways can 8 letters be arranged
Five numbers can be arranged in 5! = 120 ways.
720
4! = 24, they can be arranged in 24 different ways
In how many distinct ways can the letters of the word MEDDLES be arranged?
For the first spot, you can choose any one of 5 students. For the second spot, you can choose any one of the remaining 4 students. For the third spot, you can choose any one of the remaining 3 students. etc. So the answer is: 5x4x3x2x1 = 120
They can't be arranged in a million different ways!
raisesiresrises------------------------------------They can be arranged in 5!=120 ways.
9 ways
10*9*8 = 720
It can be arranged in six possible ways.