24
24 (You said "arrange" rather than "use," so I assume you want to use each digit only once).There are 4 choices for the first digit. Once you choose it, you have 3 choices left for the second digit. Likewise, you have 2 choices for the third digit and only one choice for the 4th digit.Thus, you have 4 x 3 x 2 x 1 = 24 ways of making a 4 digit number with these digits.
Assuming no repeats and possible can start with the zero: First digit can be one of 5, second digit can be one of 4 etc, so there a re 5 x 4 x 3 x 2 possibles ie 120
24 = 4*3*2*1
There are 17 such numbers.
30
4! = 4 * 3 * 2 * 1 = 24 ways[1]
24 (You said "arrange" rather than "use," so I assume you want to use each digit only once).There are 4 choices for the first digit. Once you choose it, you have 3 choices left for the second digit. Likewise, you have 2 choices for the third digit and only one choice for the 4th digit.Thus, you have 4 x 3 x 2 x 1 = 24 ways of making a 4 digit number with these digits.
Assuming no repeats and possible can start with the zero: First digit can be one of 5, second digit can be one of 4 etc, so there a re 5 x 4 x 3 x 2 possibles ie 120
24 = 4*3*2*1
There are 17 such numbers.
30
A Thousand digit number will have 999 zeros
There are 5 numbers which can make the 3 digit numbers in this example. Therefore each digit in the 3 digit number has 5 choices of which number can be placed there. Therefore number of 3 digit numbers = 5 x 5 x 5 = 125
120
A palindromic number can have as few as one digit, and as many as infinity. The smallest palindromic number is zero and the largest is '999... to infinity'.
Six of them.
The first 8 digit number is 10,000,000, the last is 99,999,999 which means there are 90,000,000 8 digit numbers