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In how many ways can you arrange the numbers 2 4 6 and 8 to make a four-digit number?
24 (You said "arrange" rather than "use," so I assume you want to use each digit only once).There are 4 choices for the first digit. Once you choose it, you have 3 choices left for the second digit. Likewise, you have 2 choices for the third digit and only one choice for the 4th digit.Thus, you have 4 x 3 x 2 x 1 = 24 ways of making a 4 digit number with these digits.
In how many ways can you arrange the numbers 0 2 4 6 and 8 to make a four-digit number?
Assuming no repeats and possible can start with the zero: First digit can be one of 5, second digit can be one of 4 etc, so there a re 5 x 4 x 3 x 2 possibles ie 120
How many 4 digit numbers can you make out of this 4 digit number 1234?
24 = 4*3*2*1
How many digit numbers can be formed from the digit 2 3 5 7 8?
To determine how many digit numbers can be formed using the digits 2, 3, 5, 7, and 8, we need to consider the number of digits in the numbers we are forming. For a 1-digit number, we can use any of the 5 digits. For a 2-digit number, we can choose 2 out of the 5 digits and arrange them, giving us (5 \times 4) combinations. We can continue this for 3-digit, 4-digit, and 5-digit numbers, which will yield (5), (20), (60), and (120) respectively. Therefore, the total number of digit numbers is (5 + 20 + 60 + 120 = 205).
How many 4 digit numbers can you make with 4760 using each digit once?
To form 4-digit numbers using the digits 4, 7, 6, and 0, we must ensure that the first digit is not 0. The valid choices for the first digit are 4, 7, or 6, giving us 3 options. After choosing the first digit, we can arrange the remaining 3 digits in any order, resulting in (3! = 6) arrangements for each choice of the first digit. Thus, the total number of 4-digit numbers is (3 \times 6 = 18).
In how many ways can you arrange the numbers 6 7 8 and 9 to make a four-digit number?
4! = 4 * 3 * 2 * 1 = 24 ways[1]
In how many ways can you arrange the numbers 2 4 6 and 8 to make a four-digit number?
24 (You said "arrange" rather than "use," so I assume you want to use each digit only once).There are 4 choices for the first digit. Once you choose it, you have 3 choices left for the second digit. Likewise, you have 2 choices for the third digit and only one choice for the 4th digit.Thus, you have 4 x 3 x 2 x 1 = 24 ways of making a 4 digit number with these digits.
In how many ways can you arrange the numbers 0 2 4 6 and 8 to make a four-digit number?
Assuming no repeats and possible can start with the zero: First digit can be one of 5, second digit can be one of 4 etc, so there a re 5 x 4 x 3 x 2 possibles ie 120
How many 4 digit numbers can you make out of this 4 digit number 1234?
24 = 4*3*2*1
How many digit numbers can be formed from the digit 2 3 5 7 8?
To determine how many digit numbers can be formed using the digits 2, 3, 5, 7, and 8, we need to consider the number of digits in the numbers we are forming. For a 1-digit number, we can use any of the 5 digits. For a 2-digit number, we can choose 2 out of the 5 digits and arrange them, giving us (5 \times 4) combinations. We can continue this for 3-digit, 4-digit, and 5-digit numbers, which will yield (5), (20), (60), and (120) respectively. Therefore, the total number of digit numbers is (5 + 20 + 60 + 120 = 205).
How many 4 digit numbers can you make with 4760 using each digit once?
To form 4-digit numbers using the digits 4, 7, 6, and 0, we must ensure that the first digit is not 0. The valid choices for the first digit are 4, 7, or 6, giving us 3 options. After choosing the first digit, we can arrange the remaining 3 digits in any order, resulting in (3! = 6) arrangements for each choice of the first digit. Thus, the total number of 4-digit numbers is (3 \times 6 = 18).
How many 4 digit numbers can you form with the numerals 2695 without repeating any digit?
To form a 4-digit number using the digits 2, 6, 9, and 5 without repeating any digit, you can use all four digits. The number of ways to arrange 4 digits is calculated as 4! (4 factorial), which equals 24. Therefore, you can form 24 different 4-digit numbers with the numerals 2695 without repeating any digit.
How many three digit number can you make from the numbers 2 3 4 7?
30
How many three digit numbers have odd prime number as 1st digit A prime number as 2nd digit and an odd number as 3rd digit?
There are 17 such numbers.
How many zeros does a thousand digit number have?
A Thousand digit number will have 999 zeros
How many 3-digit numbers are there using 2 4 6 8 and 9?
There are 5 numbers which can make the 3 digit numbers in this example. Therefore each digit in the 3 digit number has 5 choices of which number can be placed there. Therefore number of 3 digit numbers = 5 x 5 x 5 = 125
How many 3 digit number can be made using 135 taking each digit only once?
To form a 3-digit number using the digits 1, 3, and 5, where each digit is used only once, we can arrange these three digits in different orders. The number of different arrangements of 3 digits is calculated as 3! (3 factorial), which is 3 × 2 × 1 = 6. Therefore, a total of 6 different 3-digit numbers can be formed using the digits 1, 3, and 5.
