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240
15
The number of ways is 18C5 = 18!/(5!*13!) = 8,568 ways.
If he must include the last question, then his choices really boil down tohow many ways he can select 4 more from the remaining 11.The number of ways he can select 4 from 11 is (11 x 10 x 9 x 8) = 7,920 ways .But each group of 4 can be selected in 24 different ways.So he can only wind up with 7920/24 = 330 different groups of questions.
You have 50 ways to select the first.For each of those 50, you have 49 ways to select the second.Only 49 ways, because for each of the 50, there are only 49 left to select from.That's 50 x 49 ways to select the first and the second.For each of those 50 x 49 ways, you have 48 ways to select the third.That's 50 x 49 x 48 ways to select the first, second and third.For each of those 50 x 49 x 48 ways, you have 47 ways to select the fourth.That's 50 x 49 x 48 x 47 ways to select the first, second and third and fourth.But if it doesn't matter what order they are selected in, the same four people have been counted multiple times. For example, if people A, B, C and D have been selected, we will have counted A, B, C and D as one way, and D, C, B and A as another, B, D, A and D as another. In fact, there are 4 x 3 x 2 x 1 ways of counting any four people.So if order does not matter, there are (50 x 49 x 48 x 47) / (4 x 3 x 2 x 1) ways.How many ways can 5 finalists be selected from 100 people?
add ore people
240
15
Because he is races
The number of ways is 18C5 = 18!/(5!*13!) = 8,568 ways.
The answer is 11C2 * 8C3 = 55*56 = 3080 ways.
If he must include the last question, then his choices really boil down tohow many ways he can select 4 more from the remaining 11.The number of ways he can select 4 from 11 is (11 x 10 x 9 x 8) = 7,920 ways .But each group of 4 can be selected in 24 different ways.So he can only wind up with 7920/24 = 330 different groups of questions.
It is: 15C7 = 6435 combinations
You have 50 ways to select the first.For each of those 50, you have 49 ways to select the second.Only 49 ways, because for each of the 50, there are only 49 left to select from.That's 50 x 49 ways to select the first and the second.For each of those 50 x 49 ways, you have 48 ways to select the third.That's 50 x 49 x 48 ways to select the first, second and third.For each of those 50 x 49 x 48 ways, you have 47 ways to select the fourth.That's 50 x 49 x 48 x 47 ways to select the first, second and third and fourth.But if it doesn't matter what order they are selected in, the same four people have been counted multiple times. For example, if people A, B, C and D have been selected, we will have counted A, B, C and D as one way, and D, C, B and A as another, B, D, A and D as another. In fact, there are 4 x 3 x 2 x 1 ways of counting any four people.So if order does not matter, there are (50 x 49 x 48 x 47) / (4 x 3 x 2 x 1) ways.How many ways can 5 finalists be selected from 100 people?
52?
The number of ways varies, depending on the country. It would be best to select "membership" on the main site, select your country, and see what options there are for your specific country.
once as 10x10=100