The amount of brass cannot be measured in terms of its area. It must be measured in terms of its volume (or mass) because the answer will depend on the thickness of the brass.
The diagonal 'D' of the rectangle is the hypotenuse of a right triangle, whose legs are the rectangle's width 'W' and height 'H'. According to old Pythagoras: D2 = W2 + H2 D = sqr-root (W2 + H2) = sqr-rt(62 + 82) = sqr-rt(36 + 64) = sqr-rt(100) = 10 In a rectangle, the diagonals are equal, so their sum is 2D = 20.
231 m2 is about 2,486.5 square feet.
£15.45p but this may increase in future years.
sqr(-30) is i*sqr(30) We use i to represent the sqr(-1) because it is called an imaginary number. It takes an imagination to work with it. It is not fictitious.
54 = 625 (to find out sqr rt 625 then sqr rt again)
You can't convert that.
1 decimal is how much sqr meeter
8(1st eight) +8(2nd eight)= 16-> sqr(16)=4 -> sqr(4)=2 ; 8(3rd eight)-2=6
The sin of 30 is sqr(3)/2 so 6 * sqr(30) is 6 * sqr(3)/2 this is also 6/2 * sqr(3) which simplifies to 3 * sqr(3) which is approximately 5.19615242
The diagonal 'D' of the rectangle is the hypotenuse of a right triangle, whose legs are the rectangle's width 'W' and height 'H'. According to old Pythagoras: D2 = W2 + H2 D = sqr-root (W2 + H2) = sqr-rt(62 + 82) = sqr-rt(36 + 64) = sqr-rt(100) = 10 In a rectangle, the diagonals are equal, so their sum is 2D = 20.
Area is not measured in centimeter units. It may be guessed that the question should have indicated the area in square centimeters.The area of a regular pentagon is given as:A = s * s * sqr(25 + 10*(sqr(5)) / 4Solve for s:s = 2 * sqr (A / sqr(25 + 10*(sqr(5)))Insert the area of 600 square centimters:s = 2 * sqr (600 cm*cm / sqr(25 + 10*(sqr(5)))s = aproximately 19.67 cm
231 m2 is about 2,486.5 square feet.
£15.45p but this may increase in future years.
sqr(-30) is i*sqr(30) We use i to represent the sqr(-1) because it is called an imaginary number. It takes an imagination to work with it. It is not fictitious.
x=81
110
x=81