Area is not measured in centimeter units. It may be guessed that the question should have indicated the area in square centimeters.
The area of a regular pentagon is given as:
A = s * s * sqr(25 + 10*(sqr(5)) / 4
Solve for s:
s = 2 * sqr (A / sqr(25 + 10*(sqr(5)))
Insert the area of 600 square centimters:
s = 2 * sqr (600 cm*cm / sqr(25 + 10*(sqr(5)))
s = aproximately 19.67 cm
regular pentagon area of 12 000 m2 and an apothem of 40 m regular pentagon area of 12 000 m2 and an apothem of 40 m need to figure it out from area 12000 m2
A regular pentagon with a radius (apothem) of 5.1 units cannot have sides of 7.5 units and, conversely, a regular pentagon with sides of length 7.5 units cannot have a radius of 5.1 units. The figure is, therefore, impossible.
Apothem length: 4.82 35.35 square units APEX
If you mean a pentagonal prism, then find the area of the pentagon 1st. Length of 1 side x 1.7, then multiply by the height of the prism. But I dont really know the regular Pentagon volume. sorry... hope you dont hate me for that.
divide the pentagon into 5 equilateral triangles, and calculate their area. (base times height divided by 2) and when you have your answer, multiply it by 5.
What is the area of a regular pentagon with side length of 9.4 feet and an apothem length of 6.5 feet
That depends on the size of the pentagon, and whether it is regular or not. In general, you can divide the pentagon into three triangles, and calculate the area of each triangle separately.
Area = 440.44 sq feet
regular pentagon area of 12 000 m2 and an apothem of 40 m regular pentagon area of 12 000 m2 and an apothem of 40 m need to figure it out from area 12000 m2
The area (A) formula of a regular pentagon of side length (a) is: A = [a2x(25+10x51/2)1/2]/4 See the why in the development of such formula in the weblink below.
A regular pentagon has five (5) equilateral triangles within it. Find the area of each triangle (1/2bh where b is the base of the triangle or the length of a side of the pentagon, and h is the height of the triangle or the apothem of the pentagon) and multiply the area of the triangle times five (5).
The answer is 171.275*apex*
85.30
You didn't say it was a regular pentagon. For an arbitrary pentagon, you would calculate its area as you would for any polygon: divide it up into triangles, and add up the areas of the triangle. The area of a triangle is 1/2 times the base times the height, the height being the length of the perpendicular dropped to the base from the opposite vertex.
V = (1/3) (area of the base) (height) Area of a pentagon = 1/2 x apothem length x 5 x length of a side of the pentagonthe apothem is the perpendicular distance from the center of the pentagon to the side of the pentagon
The area of a pentagon of side length t is given by the formula t2 (sqrt 25 + 10 (sqrt 5)) / 4, or 5t2 tan (54o) / 4. In this case, a pentagon with one side of 10cm has an area of 102 (sqrt 25 + 10 (sqrt 5)) / 4 = 172.05 cm2 (accurate to two decimal places).
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