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How much caustic soda is required to neutralize a 25ml HCl solution at pH 3?
Wiki User
∙ 11y ago
One step at a time.
1/103 = 0.001 M HCl, so.....
Molarity = moles of solute/Liters of solution ( 25 ml = 0.025 Liters )
0.001 M HCl = X moles HCl/0.025 Liters
= 2.5 X 10 - 5 moles HCl
========================now, balanced eqiation
NaOH + HCl --> NaCl + H2O ( all one to one )( now drive reaction towards mass NaOH )
2.5 X 10 - 5 moles HCl (1 moles NaOH/1 mole HCl)(39.998 grams/1 mole NaOH)
= 10 -4 grams caustic soda needed
==========================
Wiki User
∙ 11y ago
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