add 25ml more of solution
x * 20 = 100 * 25
x = 25
dissolve 10g of TCA in 100ml distilled water.
25% ammonia solution means 25g Ammonia in 100ml of water. To convert it into moles i.e for 1000ml solvent, 25x100=250 which means 250g of ammonia is present in 1000ml of water to make a 25%solution. To convert it into molar solution we will divide 250 by the molecular mass of ammonia i.e 17. 250/17= 14.71M This means that 25% ammonia solution contains 14.71 moles of ammonia. Now we will use the formula M1V1=M2V2 Let's say we want to make 10 molar solution in 500ml water. Then, M1=14.71 V1=? M2=10 V2=500 Putting values in the above equation: 14.71xV1 = 10x500 V1 = 10x500 / 14.71 = 340ml We will take 340ml of the 25% ammonia solution and make the volume up to 500ml with water. This will be our 10 molar solution of Ammonia.
percent concentration = (mass of solute/volume of solution) X 100 To solve for mass of solute, mass of solute = (percent concentration X volume of solution)/100 So, mass of solute = (10% X 100mL)/100 = 10g
0.06% W/V = 0.06g / 100ml = 60mg/100ml = 0.6mg/ml
Very simply 1g of ammonium thiocyanate and 100g (100ml) of water!
dissolve 10g of TCA in 100ml distilled water.
A solution with the highest concentration of solute will contain the largest volume of solvent in 100mL. This means a dilute solution with a low amount of solute will have the highest volume of solvent remaining.
To prepare a 2% solution of ferric chloride in 100ml of water, you would need to add 2 grams of ferric chloride. This is calculated by multiplying the volume of the solution (100ml) by the desired concentration (2%) and converting it to grams.
It means that 100mL of solution has 75g of solute dissolved in it.
51% typically means 51% by volume. So if you have a 100ml bottle of 51% alcohol, you have 51ml of pure alcohol inside the bottle, diluted to a final solution volume of 100ml.
Simple equality. (100ml)(7%) = (500ml)(X%) = 1.4%
20 ml
A 10ml solution of 10 percent means that there are 10 grams of solute in 100ml of solution. Therefore, in 10ml of this solution, there would be 1 gram of the solute, as 10% of 10ml is 1ml of pure solute, which weighs 1 gram if the solute's density is 1 g/ml.
To make a 100ml 1M solution of Sodium Chloride, you would dissolve 5.85 grams of NaCl in enough water to make 100ml of solution. This molarity calculation is based on the molar mass of NaCl (58.44 g/mol).