4,200 J/kgC
(83-4) x 8kg x 4,200 = 2,654,400 joules
there are no calories in water you idiot
.02 btu
one calorie of heat is able to raise one gram of water one degree Celsius so 400 calories could raise 1g of water 400 degrees, so it would raise the 80g by(400/80) 5 degrees Celsius plus the initial temp of 10 degrees, the 80g of water would have a final temp of 15 degrees Celsius
6 Calories
Multiplying: (spec.heat J.kg-1.K-1)*(masskg)*(temp.difference K or oC)= Heat needed (J)128 (J.kg-1.K-1) * 500 (kg) * 50 (K) = 3.2*106 J = 3200 kJSpecial Notes:J is Joule, SI unit for energy !!Temp. difference in Kelvin (K) = same in degree Celsius (oC)Spec. heat of Lead is 128 (J.kg-1.oC-1), not 750 !!but of Potassium 750 (J.kg-1.oC-1)
2,641,760J...
2,641,760J...
mmmm enthalpy
The number of calories required will depend on the mass of water which is to be heated.
42 J
there are no calories in water you idiot
15.37684 joules
Q=mcΔT Q=14 x 4200 x 21.6 Q=1270080J
it can be made to boil at 105 degrees Celsius if we add impurities to it,as impurities raise the boiling point.
3.50 J
(5)(3)= 15 calories. 1 calorie is the energy (heat) to raise 1 gram of water by 1 degree celsius, so 5 grams of water (3 degrees Celsius) = 15.
1935 J (apex)