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How much heat is required to raise 70 kg of iron 10 degrees in celsius?
Wiki User
∙ 14y ago
The formula to use is Q=mc∆T
heat transfered=(mass)(specific heat)(change in temperature)
Iron's specific heat is 0.46, mass is 70 kg, and the change in temp is 10.
The equation will look like this:
Q=(70)(.46)(10)
Q=322kJ
Wiki User
∙ 14y ago
Wiki User
∙ 11y ago1353000
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