I = C*R*T
328 = C*0.025*3
So C = 328/0.075 = 4373.33 (approx)
Let P be the amount of invested money. Then, .08P = 336 P = 336/.08 = 4,200
$210.00
an investmntment of 4000 is made at an annual simple interest rate of 8%. How much additional money must be invested at 12% so that the total interest earned is 1640?
Two equations. x+y=56000 .07x=.05y Solve both of these equations simultaneously and it will be the answer. x+(.07/.05 x)=56000
300 :D
7% of 3,000 for 6 month
Kate invested 4500.
It was eight years.
Let P be the amount of invested money. Then, .08P = 336 P = 336/.08 = 4,200
A $5000 investment at an annual simple interest rate of 4.4% earned as much interest after one year as another investment in an account that earned 5.5% annual simple interest. How much was invested at 5.5%?
$210.00
72
an investmntment of 4000 is made at an annual simple interest rate of 8%. How much additional money must be invested at 12% so that the total interest earned is 1640?
Two equations. x+y=56000 .07x=.05y Solve both of these equations simultaneously and it will be the answer. x+(.07/.05 x)=56000
Simple interest = 700*5/100*2 = 70Simple interest = 700*5/100*2 = 70Simple interest = 700*5/100*2 = 70Simple interest = 700*5/100*2 = 70
300 :D
1 year