The word "more" is comparative and therefore there needs to be at least two scenarios that are being compared. There is only one given in the question.
Let P be the amount of invested money. Then, .08P = 336 P = 336/.08 = 4,200
2.25
Two equations. x+y=56000 .07x=.05y Solve both of these equations simultaneously and it will be the answer. x+(.07/.05 x)=56000
an investmntment of 4000 is made at an annual simple interest rate of 8%. How much additional money must be invested at 12% so that the total interest earned is 1640?
T = 3yrs
Kate invested 4500.
Let P be the amount of invested money. Then, .08P = 336 P = 336/.08 = 4,200
A $5000 investment at an annual simple interest rate of 4.4% earned as much interest after one year as another investment in an account that earned 5.5% annual simple interest. How much was invested at 5.5%?
You invested $15,000 in two accounts paying 6% and 8% annual interest, respectively.
2.25
Two equations. x+y=56000 .07x=.05y Solve both of these equations simultaneously and it will be the answer. x+(.07/.05 x)=56000
1/12th of 5% because there are 12 months in a year. ANSWER:- 1/60th per cent, which is the same as 0.01667 of the amount invested.
an investmntment of 4000 is made at an annual simple interest rate of 8%. How much additional money must be invested at 12% so that the total interest earned is 1640?
T = 3yrs
The annual (or annualised) interest rate.
Sorry I really don't know.
7% of 3,000 for 6 month