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200 newton-meters per second = 200 watts.
To lift a 950-N load 3 meters requires (950 x 3) = 2,850 joules of energy.The power is the rate at which the energy is delivered. It takes more powerto lift the load faster.The power used to lift this load is (2,850 joules) divided by (the number of seconds it takes),and the unit of the answer is watts.
Approx 2.62 hp
If you mean vertical speed, you would need to know the amount of lift it's generating, its cross-sectional area and its drag factor (at least!). More info needed.
No, that is 9x 2 = 18 N-m tryingto lift 9 x 3 = 27 N-m moment. The force x distance applied has to be greater
The power during the lift is (weight of the barbell in Newtons)/4.4 watts.Note:Power is not "expended". Energy is. Power is the rate at which energy is expended.
200 newton-meters per second = 200 watts.
Power = (energy) / (time) =(200 newtons x 4 meters) / (4 seconds) =200 newton-meters per second = 200 watts
To lift a 950-N load 3 meters requires (950 x 3) = 2,850 joules of energy.The power is the rate at which the energy is delivered. It takes more powerto lift the load faster.The power used to lift this load is (2,850 joules) divided by (the number of seconds it takes),and the unit of the answer is watts.
3000
The work done by applying a force in the same direction of motion is force times distance. So in this case W = F x d = 250 x 15 = 3750 J. Power is work divided by time: P = 3750 J / 10 s = 375 J/s
2 horsepower = roughly 1500 watts = 1500 newton-meters per second.Weight of 150 kg = m g = roughly 1500 newtons1500 newton-meters per second = (1500 newtons) x 1 meter per second
From the question, it's hard to tell whether the 20 meters is the vertical lift, or a horizontal transfer that occurs after the lift.If the 20 meters is the vertical lift (performed by a very large fork-lift in a shop with a very high ceiling):Energy = work = 400 N times 20 m = 8,000 Newton-meters = 8,000 joules8,000 joules in 50 seconds = 8,000 / 50 = 160 joules per second = 160 watts = about 0.214 horsepower.If the 20 meters is a horizontal ride after the lift is complete, then that part of the move consumes nominally no energy or power. No force is required to move an object perpendicular to the force of gravity. Whatever force is applied initially, to get the crate moving, is returned at the end of the 20 meters, when reverse force must be applied to the crate in order to make it stop moving.
We have no way of knowing what power the machine was rated for, but with the information given in the question, we can calculate the power it delivered during the crate-lift: It was (1.96) x (mass of the crate in kilograms) x (distance the crate was lifted in meters) watts.
If it takes 3400J to lift a rock onto a ledge, what power is required to lift the rock onto the ledge in 4 seconds Power is energy per unit time. It is measured in watts (joules per second). As such if 3400 joules is transfeered in 4 seconds, the power equals 3400 / 4. The power required is therefore 850 watts.
Approx 2.62 hp
Raising 250 kg by 2 meters = 500 kgm-meters = 500 Joules of potential energy added to the load.If this maneuver is accomplished in 2 seconds, then the rate of delivering energy to the load is500/2 = 250 joules per second = 250 watts = roughly 1/3rd horsepower.