The power during the lift is (weight of the barbell in Newtons)/4.4 watts.
Note:
Power is not "expended". Energy is. Power is the rate at which energy is expended.
n nk
First you calculate the energy required to lift the object: potential energy = mgh (mass x gravity x height). Note that your problem statement doesn't mention the height - you need that, too. Energy will be in Joule. Then you divide the energy by the time, to get power (in Watt).
Power = energy/time = 50/5 = 10 watts
9060 sec. (Apex)
A quadrillion is 10 to the 15th power. This is illustrated even more when you convert that to years (in seconds, not days). 1 year = 365 days. 365 days is 31,536,000 seconds (60 seconds * 60 minutes * 24 days * 365 days). 10 to the 15th power divided by 31,536,000 seconds = 31709791.983764585 years. Rounded up that is 31,709,792 years.
n nk
To calculate power, you can use the formula: Power = Work / Time. In this case, the work done is 425 J and the time taken is 10.5 seconds. Plugging these values into the formula, the power expended by the boy to pull the sled up the hill is 40.48 watts.
The power expended is 50 Watts. Power is calculated by dividing the work done (force x distance) by the time taken. In this case, the work done is 50N x 3m, which is 150 Joules, and dividing this by 3 seconds gives 50 Watts.
The power expended to lift the 100 N box a distance of 2 meters in 1.0 second is 200 Watts. This is calculated by multiplying the force of 100 N by the distance of 2 meters divided by the time of 1.0 second.
measure of weight lifted regardless of time
Henry 2
The work done on the object is 200 Joules, as work is calculated by multiplying force by distance. The power expended to lift the object is 40 Watts, as power is calculated by dividing work by time. The gravitational potential energy gained by the object is 200 Joules, as the work done becomes stored as potential energy in the object.
Power is defined as work over time. Thus, we must first calculate the work involved in moving the barbell. W = Fd = 150 lbs * 2 ft = 300 ft-lbs per rep The work expended over the entire work out is thus 30 * 300 ft-lbs = 9000 ft-lbs. Since P = W/t, the power output is P = 9000 ft-lbs/10s = 900 ft-lbs/sec, which is about 1222 watts.
A joule / second is a watt. The watt is a unit of power. In general terms, power means energy expended, produced, or transferred, per time unit.A joule / second is a watt. The watt is a unit of power. In general terms, power means energy expended, produced, or transferred, per time unit.A joule / second is a watt. The watt is a unit of power. In general terms, power means energy expended, produced, or transferred, per time unit.A joule / second is a watt. The watt is a unit of power. In general terms, power means energy expended, produced, or transferred, per time unit.
There is no such thing as 'electric power'. Power is simply a rate: the rate at which energy is expended.
10p
The work done to lift the object is 200 J (Work = Force x Distance). The power exerted to lift the object is 40 watts (Power = Work / Time).