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18% of 330 = 59.4
So there are 59.3ml of pure acid in 330ml of 18% acid solution.
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∙ 13y ago
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How much pure acid should be mixed with 5 gallons of 70 percent acid solution in order to get a 90 percent acid solution?
x=45
How much pure acid should be mixed with 6 gallons of a 50 percent acid solution in order to get an 80 percent acid solution?
50% acid in a 6 gallon solution means that 3 gallons are acid. 9 gallons more acid will give you a total of 12 gallons of acid in a 15 gallon solution. 12 is 80% of 15.
How much pure acid should be mixed with 2 gallons of a 70 percent acid solution in order to get a 90 percent acid solution?
Set up. .70(2 gal) + X = .90(X + 2 gal) distribute 1.4 + X = .90X + 1.8 X = .90X + .4 .1X = .4 X = 4
How much water should be added to six liters of thirty percent acid solution to dilute twelve percent solution?
6 litres of 30% solution would contain 6*30/100 = 1.8 litres of pure acid.1.8 litres of pure acid, in a 12% solution means the total volume is 1.8*(100/12) = 15 litres in total. So you need to add 9 litres of pure water.6 litres of 30% solution would contain 6*30/100 = 1.8 litres of pure acid.1.8 litres of pure acid, in a 12% solution means the total volume is 1.8*(100/12) = 15 litres in total. So you need to add 9 litres of pure water.6 litres of 30% solution would contain 6*30/100 = 1.8 litres of pure acid.1.8 litres of pure acid, in a 12% solution means the total volume is 1.8*(100/12) = 15 litres in total. So you need to add 9 litres of pure water.6 litres of 30% solution would contain 6*30/100 = 1.8 litres of pure acid.1.8 litres of pure acid, in a 12% solution means the total volume is 1.8*(100/12) = 15 litres in total. So you need to add 9 litres of pure water.
How many ml of 40 percent acid should be added to pure acid to make 75 ml of 65 percent acid?
The total volume of the new acid solution is 75 mL, and this solution is 65%, so the amount of acid in this solution is (0.65)*75mL = 48.75 mLYou have two equations and two unknowns:x + y = 75(0.40)*x + (1)*y = 48.75 {0.40 represents 40% and 1 represents 100% pure}Solve and get x = 43.75 and y = 31.25, so you need 43.75 mL of the 40% acid and 31.25 mL of the pure acid.
How much pure acid should be mixed with 5 gallons of 70 percent acid solution in order to get a 90 percent acid solution?
x=45
How much pure acid must be added to 12 ounces of a 40 percent acid solution in order to produce 60 percent acid solution?
6 ounces
How much pure acid should be mixed with 2 gallons of a 50 percent acid solution in order to get an 80 percent acid solution?
pH less than 7
If 120 liters of an acid solution is 75 percent acid how much pure acid is there in the mixture?
90 litres
How much pure acid should be mixed with 6 gallons of a 50 percent acid solution in order to get an 80 percent acid solution?
50% acid in a 6 gallon solution means that 3 gallons are acid. 9 gallons more acid will give you a total of 12 gallons of acid in a 15 gallon solution. 12 is 80% of 15.
How many liters of pure acid are there in 8 liters of a 20 percent solution?
1.6
How much pure water must be mixed with 10 liters of a 25 percent acid solution to reduce it to a 10 percent acid solution?
I honestly have no idea at all...but I looked it up and saw that people explained it out to be 15 liters... I have this question on my test...so I'm putting 15.
Does Acetic acid contain alcohol?
If it is a mixture, then yes. Pure acetic acid is one hundred percent acetic acid, while vinegar is 5 or 10 percent acetic acid in water. You can make a solution of acetic acid and alcohol.
How much pure acid should be mixed with 2 gallons of a 70 percent acid solution in order to get a 90 percent acid solution?
Set up. .70(2 gal) + X = .90(X + 2 gal) distribute 1.4 + X = .90X + 1.8 X = .90X + .4 .1X = .4 X = 4
How much water should be added to six liters of thirty percent acid solution to dilute twelve percent solution?
6 litres of 30% solution would contain 6*30/100 = 1.8 litres of pure acid.1.8 litres of pure acid, in a 12% solution means the total volume is 1.8*(100/12) = 15 litres in total. So you need to add 9 litres of pure water.6 litres of 30% solution would contain 6*30/100 = 1.8 litres of pure acid.1.8 litres of pure acid, in a 12% solution means the total volume is 1.8*(100/12) = 15 litres in total. So you need to add 9 litres of pure water.6 litres of 30% solution would contain 6*30/100 = 1.8 litres of pure acid.1.8 litres of pure acid, in a 12% solution means the total volume is 1.8*(100/12) = 15 litres in total. So you need to add 9 litres of pure water.6 litres of 30% solution would contain 6*30/100 = 1.8 litres of pure acid.1.8 litres of pure acid, in a 12% solution means the total volume is 1.8*(100/12) = 15 litres in total. So you need to add 9 litres of pure water.
How many ml of 40 percent acid should be added to pure acid to make 75 ml of 65 percent acid?
The total volume of the new acid solution is 75 mL, and this solution is 65%, so the amount of acid in this solution is (0.65)*75mL = 48.75 mLYou have two equations and two unknowns:x + y = 75(0.40)*x + (1)*y = 48.75 {0.40 represents 40% and 1 represents 100% pure}Solve and get x = 43.75 and y = 31.25, so you need 43.75 mL of the 40% acid and 31.25 mL of the pure acid.
How much pure acid should be mixed with 9 gallons of a 50 percent acid solution in order to get an 80 percent acid solution?
13.5 gallonsThe 50% acid solution will contain 4.5 gallons of acid & 4.5 gallons of water.So let X be the number of gallons of pure acid to add. You can set up an equation to solve for X:(4.5 + X )------------- = 0.80 (80% solution)(9 + X)The top part of the fraction is the amount of acid in the new 80% solution & the bottom part will be the total amount of solution you have. Cross multiply and solve for x.(9+X)*(0.80) = (4.5+X)*(1)7.2 + 0.8X = 4.5 + X7.2 - 4.5 = 1X - 0.8X2.7 = 0.2XX = 2.7/0.2 = 13.5
