So you need to add 9 litres of pure water.
So you need to add 9 litres of pure water.
So you need to add 9 litres of pure water.
So you need to add 9 litres of pure water.
Let x = the amount of 20% solution Let x + 10 = the amount of the final solution. So we have: (.20)x + (.50)(10) = (.40)(x + 10) .20x + 5 = .40x + 4 .20x = 1 x = 5 liters of 20% solution of saline.
4.5 litres of a 30% solution to the appropriate quantity of the 90% solution.
Well, isn't that a lovely little problem to solve? To decrease the concentration from 25% to 20%, we need to dilute the solution. Since the concentration is decreasing by 5%, we can calculate that we need to add 60 liters of water to the 300 liters of solution to achieve the desired concentration of 20%. Just like painting, a little change can make a big difference in creating the perfect mixture.
98 mL
x=45
10 liters.
Let x = the amount of 20% solution Let x + 10 = the amount of the final solution. So we have: (.20)x + (.50)(10) = (.40)(x + 10) .20x + 5 = .40x + 4 .20x = 1 x = 5 liters of 20% solution of saline.
6 litres of 50% + 4 litres of 25%
The concentration of the diluted solution will be 15(300/1000) = 4.5 %, if the percent is expressed on a weight/volume basis.
t = number of liters of 30% acid solution s = number of liters of 60% acid solution t+s=57 .30t+.60s=.50*57 t=57-s .30(57-s)+.60s=.50*57 .30*57 -.30s +.60s = .50*57 .30s = .50*57 - .30*57 = .20*57 s = .20*57/.30 = 38 liters of 30% solution t = 57 - s = 57-38 = 19 liters of 60% solution
4.5 litres of a 30% solution to the appropriate quantity of the 90% solution.
Jorge needs to add 2 liters of water to the 30% acid solution to make a 25% acid solution. This can be calculated using a dilution formula: initial acid amount / final total amount = final acid concentration.
Well, isn't that a lovely little problem to solve? To decrease the concentration from 25% to 20%, we need to dilute the solution. Since the concentration is decreasing by 5%, we can calculate that we need to add 60 liters of water to the 300 liters of solution to achieve the desired concentration of 20%. Just like painting, a little change can make a big difference in creating the perfect mixture.
How much 50 percent antifreeze solution and 40 percent antifreeze solution should be combined to give 50 gallons of 46 percent antifreeze solution?
30 liters of a 10 % solution of fertilizer has .1(30) = 3 liters of fertilizer 1 liter of 30% solution has .3 liter of fertilizer 10 liters of 30% solution has 3 liters of fertilizer so, the chemist needs 10 liters of the 30% solution and 20 liters of water to make 30 liters of a 10% solution.
A dilute solution of muriatic acid is used by the pros.
2%