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How much pure water must be mixed with 10 liters of a 25 percent acid solution to reduce it to a 10 percent acid solution?
Wiki User
∙ 13y ago
I honestly have no idea at all...but I looked it up and saw that people explained it out to be 15 liters... I have this question on my test...so I'm putting 15.
Wiki User
∙ 13y ago
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If 5 liters of a 4 percent silver iodide solution must be mixed with a 10 percent solution to get a 6 percent solution How many liters of the 10 percent solution are needed?
2.5 is the answer....5(.04)+.10(x)= .06(5+x).2+.1x=.3+.06x.04x=.1or 4x=10 so x =2.5
A solution of 30 percent acid and a solution of 60 percent acid are to be mixed to produce 50 liters of 57 percent acid How many liters of each solution should be used?
t = number of liters of 30% acid solution s = number of liters of 60% acid solution t+s=57 .30t+.60s=.50*57 t=57-s .30(57-s)+.60s=.50*57 .30*57 -.30s +.60s = .50*57 .30s = .50*57 - .30*57 = .20*57 s = .20*57/.30 = 38 liters of 30% solution t = 57 - s = 57-38 = 19 liters of 60% solution
If 4kg of chemical are mixed with water to make up 200 liters of solution what is the percentage strength of the solution?
0.04M
How many gallons of a 12 percent indicator solution must be mixed with a 20 percent indicator solution to get 10 gallons of a 14 percent solution?
10 gallons..
If 25 moles of sucrose are mixed into 50 liters of water what is the molarity?
Molarity = moles of solute/Liters of solution Molarity = 25 moles sucrose/50 liters H2O = 0.5 M sucrose
How many liters of 10 percent alcohol solution must be mixed with 70 liters of a 70 percent solution to get a 30 percent solution?
210Type your answer here...
A pharmacist mixed a 20 percent solution with a 30 percent solution to obtain 100 liters of a 24 percent solution How much of the 20 percent solution did the pharmacist use in the mixture?
A pharmacist mixed a 20 percent solution with a 30 percent solution to obtain 100 liters of a 24 percent solution. How much of the 20 percent solution did the pharmacist use in the mixture (in liters).
How many liters of a 50 percent alcohol solution must be mixed with 40 liters of a 90 percent solution to get a 60 percent solution?
mary mixed 2l of an 80% acid solution with 6l of a 20% acid solution. what was the percent of acid in the resulting mixture
How many liters of a 90 percent acid solution must be mixed with a 15 percent acid solution to get 600 L of a 80 percent solution?
Mixing 80 liters of 15% solution and 520 liters of 90% solution will give 600 liters of 80% solution.
Pharmacist mixed a 20 percent solution with a 30 percent solution to obtain 100 liters of a 24 percent solution How much of the 20 percent solution did the pharmacist use in the mixture?
10
A solution containing 30 percent insecticide is to be mixed with a solution containing 50 percent insecticide to make 200 L of a solution containing 42 percent insecticide How much of the 30 percent i?
80 liters
Determine the strength of a polymer solution as a percent if 80 grams of polymer are mixed with 16 liters of water?
0.1125% of polymer solution.
If 5 liters of a 4 percent silver iodide solution must be mixed with a 10 percent solution to get a 6 percent solution How many liters of the 10 percent solution are needed?
2.5 is the answer....5(.04)+.10(x)= .06(5+x).2+.1x=.3+.06x.04x=.1or 4x=10 so x =2.5
A chemist has one solution which is 50 percent acid and a second solution which is 25 percent acid how much of each should be mixed to make a 10 liters of a 40 percent acid solution?
6 litres of 50% + 4 litres of 25%
How many liters of a 20 percent alcohol must be mixed with 40 liters of a 90 percent solution to get a 60 percent solution?
Let L be the liters to be added. Then (L) x (0.2) + (40 x 0.9) = (L + 40) x 0.6 0.2L + 36 = 0.6L + 24 36 - 24 = (0.6 - 0.2)L 12 = 0.4L L = 12/0.4 = 120/4 = 30 Liters
A solution of 30 percent acid and a solution of 60 percent acid are to be mixed to produce 50 liters of 57 percent acid How many liters of each solution should be used?
t = number of liters of 30% acid solution s = number of liters of 60% acid solution t+s=57 .30t+.60s=.50*57 t=57-s .30(57-s)+.60s=.50*57 .30*57 -.30s +.60s = .50*57 .30s = .50*57 - .30*57 = .20*57 s = .20*57/.30 = 38 liters of 30% solution t = 57 - s = 57-38 = 19 liters of 60% solution
What quantity x of a 65 percent acid solution must be mixed with a 20 percent solution to produce 300 mL of a 45 percent solution?
133.33
