this is the formula R=E/I. 120/6=20 ohms of resistance.
There are zero amps in 3000 volts. A load needs to be connected to the voltage.
It's not that simple. The basic formula is Volts / Ohms = Amps. For 30 Volts you'd get 0.5 Amps, for 60 Volts you'd get 1 Amp, for 120 Volts you'd get 2 Amps.
Watts is the product of amps x volts. To give an answer the amperage needs to be given.
The equation that needs to be used is I = W/E. Amps = Watts/Volts. Amps = 500/240 = 2.08 amps.
To calculate the amps for a jump starter with 500 watts, you can use the formula: Amps = Watts / Volts. If assuming a standard 12-volt car battery, the calculation would be 500 watts / 12 volts = 41.67 amps.
The formula to calculate the relationship between amps, volts and watts is Volts X Amps = Watts or Volts = Watts / Amps or Amps = Watts / Volts therefore; 200 Watts divided by 1.95 Amps is 102.5641 Volts.
Ohm's law: Volts = Amps * Ohms, or Amps = Volts / Ohms 12 volts / 0.5 ohms = 24 amps
To answer this question a current value needs to be given. 125000 is the product of amps times volts. I = W/E = 521 amps. So to bring 240 volts up to 125 KVA you need the circuit load to draw 521 amps.
To answer this question a voltage needs to be stated. Wire is sized by the amount of amperage the load takes. W = Amps x Volts. Amps = 650/ volts.
To convert watts to amps at 120 volts, use the formula: Amps = Watts / Volts. For 1500 watts at 120 volts, the calculation would be: 1500 watts / 120 volts = 12.5 amps.
4 volts and how many amps? Watts = amps x volts. It depends on the amount of current (in Amps) flowing at 4 Volts... See Ohms Law: Watts = Volts x Amps If you have 2 Amps flowing at 4 Volts you are dissipating/consuming 8 Watts. If you have 10 Amps flowing at 4 Volts you are dissipating/consuming 40 Watts.
6 amps.