Outer volume = pi*142*40 cm3
Inner volume = pi*122*40 cm3
Volume of steel = Outer volume - Inner volume = pi*(142 - 122)*40 cm3
= pi*52*40 = 6535 cm3 approx.
Consider the volume of the pipe as the difference in the volume of two cylinders, one containing the whole pipe and the other the empty space inside. Use the formula for the volume of a cylinder : Pi*r*r*h. Find the volume of the first cylinder with the larger radius and subtract from it that of the cylinder with the smaller radius. The height (or length) is the same for both volume calculations. The result of subtracting these is the volume occupied by the pipe.
This depends on what type of steel. The density of carbon steel (one of the most common types of steel) is 7.85g/cm3Density = m/vradius of rod = 3.25mm (radius is 1/2 of diameter)3.25mm = .325 cm1 meter = 100cmvolume of cylinder = (pi)(radius)^2(h) = 33.18Density * Volume = mass7.85 * 33.18 = 260.46260.46 grams
It is: (2*pi*42)+(8*pi*6) = 203.062 square cm rounded to 3 decimal places
That depends on the thickness of the "wall."
3.14159 x radius squared x thickness x .283 (weight of 1 cubic inch of steel)
young modulus remain unaffected ...as it depends on change in length ..
The density of steel is around 490 pounds per cubic foot, depending on grade. I'm assuming the steel bar is a cylinder because you gave me a diameter. If it is not, I am completely wrong. The volume of a cylinder is pi times the radius squared times height. Pi is about 3.14159. The radius squared is 0.01085069444 feet. The height is 20 feet. The volume of the steel bar must be 0.68176866291519189 cubic feet. Therefore the bar must weigh about 334 pounds. Hmm, seems too heavy..
Low cost carbon steel caskets are usually made of 20-gauge steel. This means that 20 sheets of 20 ga steel have a thickness of one inch. Twenty-gauge steel sheets have a thickness of 0,8 mm; this is the same thickness as used in many automobile body panels. Standard steel caskets use 18 ga steel sheets which have a thickness of 1 mm. Upper end steel caskets use 16 ga steel sheets with a thickness of 1,3 mm. 16 sheets of 16 ga steel have a thickness of one inch.
By thick control.
kg = 6.16546 x width mm x OD2 x bore2 ---- 1000000
Certainly. Obviously, the design of the cylinder would need to take into consideration the properties of aluminum and the nature of the application. For example, the wall thickness of the cylinder would need to be thicker than a comparable steel cylinder for use at the same pressure.
3mm thickness of stainless steel tank. 3mm thickness of stainless steel tank.