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How much weaker will a sound be at a distance of 2 meters from the source compared to its intensity at 1 meter?
Wiki User
∙ 11y ago
Yes, it will be!
Wiki User
∙ 11y ago
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Why do sounds get quieter the further away you are from the source?
Louder or fainter means more intense or less intense of sound vibrations respectively.Intensity in turn is the energy per unit area.Imagine the source of sound to be at the centre of a sphere. When you are far away then the radius of the sphere would be larger and thus the surface area of the sphere also becomes larger.As the energy given out by the source of sound is divided by larger area to get the intensity its value becomes lesser. Hence fainter.Ear drums and microphone diaphragms are moved by sound pressure.Note: Sound power (sound intensity) is the cause - and the sound pressure is the effect. The effect is of particular interest to the sound engineer.Another Perspective:The intensity (loudness) of sound decreases with the square of the distance from the source.
What is inverse square law and an example?
inverse square law is the law that states the intensity of the light, sound etc is directly proportional to 1/ distance squared meaning the further you are from the source the less intense the light etc will be. e.g. an object 1m away from a light source 1/1^2=1 , 2m 1/2^2= 1/4 and so forth
How many meters is the thames?
If you mean the length from its source - it's 346 km (215 miles) long
To what is the illumination of a surface by a light source directly proportional?
The illumination on the surface would be reduced by a factor of four, thereforeif the distance from a light source is doubled, the illumination provided by the source is one fourth as great.
How long is a shadow cast by a person 1.9 meters tall?
It depends on where the light source is. If you're talking about the sun, it depends on what time of day it is.
How does light intensity vary with distance form the source?
Light intensity is inversely proportional to the square of the distance: I = k/d2
What happens to the intensity of ionizing radiation when you move away?
The intensity reduces in proportion to the square of your distance from the source.
How does the intensity of a sound wave change if the distance from the source increases by a factor of 2?
The intensity increases by a factor of 4-APEX
How is the intensity of a sound related to the distance between the source and the receiver?
The intensity of a sound will decrease according to an inverse square law.
What is the relationship between the intensity of the radiation given off from a radiation source and distance from the radiation source?
The source doesn't care how far you are from it, or whether you're even there, andthere's no relationship between that and the intensity of the radiation it gives off.However, the intensity of the radiation that you receivefrom it is inversely proportionalto the square of your distance from it ... same math as for gravity.
How do the amplitude and the intensity of surface water waves vary with the distance of the source?
physics
How does the intensity of a sound wave change if the distance from the source is reduced by a factor of 4?
- 6 dB is incorrect. It will decrease by 12 dB.
How does distance affect intensity of radiation?
The source doesn't care how far you are from it, or whether you're even there, andthere's no relationship between that and the intensity of the radiation it gives off.However, the intensity of the radiation that you receivefrom it is inversely proportionalto the square of your distance from it ... same math as for gravity.
How is laser light different from incandescent light?
The intensity of light from most light sources is inversely proportional to the square of the distance from the source. So the intensity two meters from an incandescent lamp is one quarter of the intensity at one meter, and at three meters from the lamp the intensity is one ninth of the intensity at one meter. Laser light ideally has the same intensity at any distance.
Why does the intensity of a sound decrease as the distance from the source increases?
the waves spread out over a larger areathe waves are absorbed by the medium as they pass through itthe waves are being scattered by irregularities in the medium and don't all proceed forwardetc.
How many candelas equals 1 lux?
They really aren't equal because they measure two different things. However, they are related to each other.The Candela is the measure of the luminous intensity of a light source. A higher Candela number means a brighter light. Lux is a measurement of light density and means lumens per square meter. Again, a greater number of lux means that the surface being illuminated by the light is is receiving more light per square meter.The formula for calculating the conversion of candelas to lux is E = I/(D*D) where E is the Illuminance of the the surface in lumens per square meter (lux), I is the Intensity of the the light source in Candelas and of course (D*D) is the square of the distance from the light source in meters.Therefore 1 Candela will illuminate a surface with 1 Lux only at one meter from a light source. At different distances it will illuminate to different densities of light.For example: Solving for E, that same one candela light source would only read 1/4 lux at two meters [ 1/(2*2)] and 1/16 lux at four meters [1/(4*4)].If you know the lux at a given distance in meters from the light source you can solve for I and it will give you the intensity of the light in Candelas. From that you can calculate the intensity of the light.For example: Solving for I, multiply the lux times the square of the distance in meters and you will have the intensity of the light source in Candelas.So a reading of 8 lux at a distance of 3 meters would mean that the light source has an intensity of 8*3*3 or 72 candelas.
How does intensity vary with distance from the source?
It's an inverse-square law - for instance, double the distance, and the intensity will be reduced by a factor 1/4.This assumes that there is nothing absorbing the light (for instance, fog); if there is, the intensity in the above example will of course be even less than 1/4 the original intensity.
