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Q: How prepare glycerol 80 percent solution?
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Show by calculation how would you prepare 200ml of 80 percent glycerol?

Take a 500ml beaker, add 160ml of glycerol. make up the volume to 200ml by adding water. Stir them with a magnetic stirrer for a while and here is your 80% Glycerol.


How many liters of a 90 percent acid solution must be mixed with a 15 percent acid solution to get 600 L of a 80 percent solution?

Mixing 80 liters of 15% solution and 520 liters of 90% solution will give 600 liters of 80% solution.


A chemist is making 200 L of a solution that is 62 percent acid He is mixing an 80 percent acid solution with a 30 percent acid solution How much of the 80 percent acid solution will he use?

128 liters


A chemist has one solution that is 80 percent acid and another solution that is 30 percent acid How much of the first 80 percent solution is needed to make a 400 L solution that is 62 percent acid?

256 liters


What is 1 percent if 45 percent is 36.00?

Solution: 36/0.45 = 80, it follows that 1% of 80 is 0.8 answer: 0.8


A chemist has one solution that is 80 percent acid and another solution that is 30 percent acid How much of the second 30 percent solution is needed to make a 400 L solution that is 62 percent acid?

144liters


How many gallons of a 90 percent antifreeze solution must be mixed with 80 gallons of 25 percent antifreeze to get a mixture that is 80 percent antifreeze?

614


A solution containing 30 percent insecticide is to be mixed with a solution containing 50 percent insecticide to make 200 L of a solution containing 42 percent insecticide How much of the 30 percent i?

80 liters


How many liters of a 50 percent alcohol solution must be mixed with 40 liters of a 90 percent solution to get a 60 percent solution?

mary mixed 2l of an 80% acid solution with 6l of a 20% acid solution. what was the percent of acid in the resulting mixture


What is the answer to 60kg of an 80 percent acid solution to produce a 50 percent solution?

In order to reduce the percentage of acid from 80% to 50%, you would need to add another 36 kg of diluent (e.g. water).


What quantity of a 80 percent acid solution must be mixed with a 30 percent solution to produce 300 mL of a 40 percent solution?

Let Q be the quantity of 80% solution required then (300 - Q) is the quantity of 30% solution as together the two solutions must equal 300. Then, [80 x Q] + [30 x (300 - Q)] = [40 x 300] 80Q + 9000 - 30Q = 12000 50Q = 3000 Q = 60...........which means (300 - Q) = 240 60ml of 80% acid solution + 240ml of 30% solution produces 300ml of 40% solution.


Now you are scoring 68 percent in diploma how to score 80 percent tell you the solution?

Raise your score by 12%.