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A chemist has one solution that is 60 percent chlorinated and another solution that is 40 percent chlorinated How much of the first 60 percent solution is needed to make a 100 L solution that is 5?

50liters


A chemist has one solution that is 60 percent chlorinated and another solution that is 40 percent chlorinated. How much of the first 60 percent is needed to make a 100 L solution that's 50 percent?

50


A chemist has one solution that is 60 percent chlorinated and another that is 40 percent chlorinated How much of each solution is needed to make a 100 liter solution that is 50 percent chlorinated?

50 Liters of the 60% solution.


A chemist has one solution that is 60 percent chlorinated and another solution that is 40 percent chlorinated How much of the first 60 percent solution is needed to make a 100 L solution that is 50?

To create a 50% chlorinated solution from the 60% and 40% solutions, the chemist will need to mix the two in equal amounts. Therefore, 50 L of the 60% solution and 50 L of the 40% solution are needed to make a 100 L solution that is 50% chlorinated.


A chemist has one solution that is 80 percent acid and another solution that is 30 percent acid How much of the first 80 percent solution is needed to make a 400 L solution that is 62 percent acid?

To create a 400 L solution that is 62% acid, you would need 200 L of the 80% acid solution and 200 L of the 30% acid solution. This would result in a final solution with the desired concentration.


When A chemist has one solution that is 80 acid and another solution that is 30 acid. How much of the first (80) solution is needed to make a 400 L solution that is 62 acid?

You need 256 litres.


How many liters of 93 percent acid solution are needed to make a 9 percent solution with 50 liters of water?

4.84


Jerry is experimenting with chemicals in the laboratory He mixes a solution that is 10 percent acid with a solution that is 30 percent acid How much of the 10 percent acid solution will be needed to m?

10 liters


A chemist has one solution that is 80 percent acid and another solution that is 30 percent acid how much of the second 30 percent solution is needed to make a 400L that is 62 percent acid?

.80x+.30y=400*.62 .80x+.30y=248 This is equation one. x+y=400 x=400-y This is the second equation. .80(400-y)+.30y=248 320-.80y+.30y=248 -.50y=-72 Y=144 X=256 CHECK .80(256)+.30(144)=400(.62) 204.8+43.2=248 248=248


How much of a 4 percent solution is needed for a 100mg dose?

2.5ml


Mary is experimenting with chemicals in the laboratory She mixes a solution that is 10 percent acid with a solution that is 25 percent acid How much of the 10 percent acid solution will be needed to m?

16 2/3 liters


How many liters of 9 percent salt solution and 18 percent salt solution are needed to make 18 liters of 10 percent salt solution?

A. 16 of 18 percent and 2 of 9 percent b. 14 of 18 percent and 4 of 9 percent c. 16 of 9 percent and 2 of 18 percent d. 14 of 9 percent and 4 of 18 percent