C2h4 + o2 ------------- co2 + h2o
c2h4 + 3o2 ------------- 2co2 + 2h2o
CH4+O2 --- CO2+H2O... All that's missing - is the number 2 before the water molecule... CH4+O2 --- CO2+2H2O
Burning alcohol First 1 C2H5OH + O2 -> 2 CO2 + 3 H2O to balance the just the carbons and hydrogens now count the oxygens in the products 4+3=7 and determine the number of oxygens: 1 C2H5OH +3 O2 -> 2 CO2 + 3 H2O
Yes.
This equation is:C2H5OH + 3 O2 = 2 CO2 + 3 H2O
The formula for glucose is C6H12O6 not C6H12O8 which I believe is what you were trying to make in a chemical equation which would look like 6H2O+6CO2 ------->C6H12O6 The rest of the atoms are converted back into H2O and any excess oxygen is given off by the plants. That is the reason that we need plants to balance the carbon dioxide and oxygen levels in the atmosphere.
The balanced equation is 2 C4H10 + 13 O2 -> 8 CO2 + 10 H2O.
The chemical reaction is:C2H5OH ----------------------------- C2H4 + H2O
This equation is C18H36 + 54 O2 = 18 CO2 + 18 H2O.
Na2CO3 + 2 HCl = CO2 + H2O + 2 NaCl
2NH4Cl + Na2CO3 --> 2NH3 + CO2 + H2O + 2NaCl
CO2 H2O- C6H12O6 6O2 6H2O is NOT a chemical reaction. Where are the reactants and the products? Is it CO2 + H2O ==> C6H12O6 + O2 ? That would be an unbalanced equation whose balanced equation would be6CO2 + 6H2O ==> C6H12O6 + 9O2 (NOTE: no H2O on the right side)
Assuming complete combustion: CH4 + 2O2 --> 2H2O + CO2.
C2H6O + 3 O2 = 2 CO2 + 3 H2O
The balanced chemical equation for cellular respiration is C6H12 O6+ O2--> CO2 + H20 + ATP
The balance equation is HI(aq) + H2O(l) ==> H3O^+(aq) + I^-(aq)
Na2CO3 + 2HCl -> 2NaCl + CO2 + H2O
C4H10 + 13/2O2 ---> 4CO2 + 5H2O(1) First balance the carbon atoms: There are 4 on the left, so you'll need 4 on the right. So put a 4 in front of CO2(2) Next balance the hydrogen atoms: there are 10 on the left, so you'll need 10 on the right. Since you have a water molecule, put 5 in front of H2O (5*2 = 10).(3) Finally balance the oxygen atoms: on the right you have 4*2 (from the carbon dioxide) + 5*1 (from the water) = 8+5 or 13. So you now need 13 atoms of oxygen on the left. So put 13/2 in front of O2 (13/2 * 2 = 13)(4) Now get rid of the fraction in front of O2 by multiplying all the coefficients by 2, to get your final balanced equation:2C4H10 + 13O2 ---> 8CO2 + 10H2O