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sin[squared]60 is the same as (sin 60)^2 or (sin 60)*(sin 60)
If you dont know the sines and cosines of a 30-60-90 triangle off the top of your head, you can enter into a calculator to find out.
sin 60 = 3^(1/2)/2 OR "The square root of three divided by two"
cos 30 = 3^(1/2)/2 OR " ' ' ' ' ' ' ' ' "
So we end up with:
[ 3^(1/2) / 2 ]^2 + [ 3^(1/2) / 2 ]^2
Since it's the same thing twice, we can say:
2 * [ 3^(1/2) / 2 ]^2
Squaring...
2 * [ 3^(1/2) / 2 ] * [ 3^(1/2) / 2 ]
2 * [ 3 / 4]
[ 6 / 4 ] = 1.5
chandan
urs...........
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∙ 14y ago
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How do you construct a triangle with perimeter 150 mm and a base angle 75 degrees and 30 degrees?
Perhaps you can ask the angel to shed some divine light on the question! Suppose the base is BC, with angle B = 75 degrees angle C = 30 degrees then that angle A = 180 - (75+30) = 75 degrees. Suppose the side opposite angle A is of length a mm, the side opposite angle B is b mm and the side opposite angle C is c mm. Then by the sine rule a/sin(A) = b/(sin(B) = c/sin(C) This gives b = a*sin(B)/sin(A) and c = a*sin(C)/sin(A) Therefore, perimeter = 150 mm = a+b+c = a/sin(A) + a*sin(B)/sin(A) + a*sin(C)/sin(A) so 150 = a*{1/sin(A) + sin(B)/sin(A) + sin(C)/sin(A)} or 150 = a{x} where every term for x is known. This equation can be solved for a. So draw the base of length a. At one end, draw an angle of 75 degrees, at the other one of 30 degrees and that is it!
Which is the 30o-60o-right triangle theorem?
If its a 300-600-right angle triangle then the third angle must be 90 degrees. Then its base squared plus its height squared equals its hypotenuse squared usually written in the form of: a2+b2 = c2
What is th formula to find the area of a hexagon?
if r = perpendicular distance center of hexagon to a side, and r^2 = r squared, then AREA = 6x r^2 x tan 30 degrees = 3.464 r^2 or if R = distance center of hexagon to a corner, AREA = 3 R^2 sin 60 = 2.598 R^2
What number squared equals 30?
5.477225575 squared equals 30.
What is the arc function for trigonometric relationships?
The trigonometric function of an angle gives a certain value The arc trigonometric function of value is simply the angle For example, if sin (30 degrees) = 0.500 then arc sine ( 0.500) = 30 degrees
How do you find cosine squared at 30 degrees?
cos(30) = sqrt(3)/2 so cosine squared is 3/4.
What is the sin theta of 30 degrees?
Sin theta of 30 degrees is1/2
Using exact values find the numerical value of sin 30 degrees cos 240 degrees plus sin 210 degrees sin 300 degrees?
SQRT(3)/4 - 1/4
What is the answer to sin of 390 degrees?
sin(360+30) =sin(30)= 1/2
What is the value of sin 30 degrees?
Sin30 degrees is 0.50000
What is the sine of 30 degrees?
sin(30) = 0.5
How do you construct a triangle with perimeter 150 mm and a base angle 75 degrees and 30 degrees?
Perhaps you can ask the angel to shed some divine light on the question! Suppose the base is BC, with angle B = 75 degrees angle C = 30 degrees then that angle A = 180 - (75+30) = 75 degrees. Suppose the side opposite angle A is of length a mm, the side opposite angle B is b mm and the side opposite angle C is c mm. Then by the sine rule a/sin(A) = b/(sin(B) = c/sin(C) This gives b = a*sin(B)/sin(A) and c = a*sin(C)/sin(A) Therefore, perimeter = 150 mm = a+b+c = a/sin(A) + a*sin(B)/sin(A) + a*sin(C)/sin(A) so 150 = a*{1/sin(A) + sin(B)/sin(A) + sin(C)/sin(A)} or 150 = a{x} where every term for x is known. This equation can be solved for a. So draw the base of length a. At one end, draw an angle of 75 degrees, at the other one of 30 degrees and that is it!
Find the value of a if tan 3a is equal to sin cos 45 plus sin 30?
If tan 3a is equal to sin cos 45 plus sin 30, then the value of a = 0.4.
What is the area of triangle having an angle A 30 degrees 20' B 50 degree10' side a 27cm?
Instead of alpha and beta for the angles, I will use A and B. Firstly, I would find the second side, b, using the sin rule which states: a/sinA = b/sinB So 27/sin(30°20') = b/sin(50°10') ==> b = 27*sin(50°10')/sin(30°20') where * means multiply ==> b = 27*0.7679/0.5050 = 41.0542 Then find the 3rd angle, C remembering the sum of the angles in a triangle is 180° C = 180 - 50°10' - 30°20' = 99° 30' Now to find the area, use the formula: Area = 1/2 * a * b * sin C ==> 1/2 * 27 * 41.0542 * sin(99°30') = 546.6308 sq cm.
The refractive index of water is 1.33 a ray is incident from water on air at an angle of incidence equal to 30 degree what is the angle of refraction in air?
nwater * sin 30=nair *sin(angle of refraction) 1.33*0.5=1*sin(angle of refraction) sin(angle of refractiob)=0.665 angle of refraction inair=41.6 degrees nwater * sin 30=nair *sin(angle of refraction) 1.33*0.5=1*sin(angle of refraction) sin(angle of refractiob)=0.665 angle of refraction inair=41.6 degrees
How do you find the area of a parallelogram if an angle is 30 degrees and the height is unknown?
You can if you know the lengths of the two pairs of sides. Thanks to the fact that sin(30) = 0.5, the height of the parallelogram is half the length of the sloping side.
Which is the 30o-60o-right triangle theorem?
If its a 300-600-right angle triangle then the third angle must be 90 degrees. Then its base squared plus its height squared equals its hypotenuse squared usually written in the form of: a2+b2 = c2
