Sin theta of 30 degrees is
1/2
4Sin(theta) = 2 Sin(Theta) = 2/4 = 1/2 - 0.5 Theta = Sin^(-1) [0.5] Theta = 30 degrees.
Sin(theta) = 0.03125 Hence theta = ArcSin(0.03125) theta = 1.790784659... degrees.
(/) = theta sin 2(/) = 2sin(/)cos(/)
You can use the Pythagorean identity to solve this:(sin theta) squared + (cos theta) squared = 1.
Since sin(theta) = 1/cosec(theta) the first two terms simply camcel out and you are left with 1 divided by tan(theta), which is cot(theta).
4Sin(theta) = 2 Sin(Theta) = 2/4 = 1/2 - 0.5 Theta = Sin^(-1) [0.5] Theta = 30 degrees.
Sin(X) = 0.9 X = Sin^(-1) 0.9 X = 64.158... degrees.
answer is 2.34 degrees answer is 2.34 degrees
Sin(theta) = 0.03125 Hence theta = ArcSin(0.03125) theta = 1.790784659... degrees.
sin (theta) = [13* sin (32o)]/8 = 13*0.529919264/8 = 0.861118804 [theta] = sin-1 (0.861118804) [theta] = 59.44o
108.435 degrees 288.435 degrees (decimal is rounded)
The equations for projectiles shouldn't just have theta, they should have sin(theta) or cos(theta). As long as you have your calculator set in the right mode, either will work when you evaluate sin or cosine. Example: Say you have a projectile launched at 30 degrees above horizontal. In order to find the y velocity, you will have to calculate sin(30) with you calculator in degree mode. If instead you called this angle pi/6 (the same angle, just in radians), you could enter sin(pi/6) in your calculator in radians mode and get the same answer.
if x if ArcSine 1.5 degrees means the sin(x)=1.5 but the range of the sin(theta) for all angles theta is between o and 1 inclusive. So there is no real answer.
COS squared Theta + SIN squared Theta = 1; where Theta is the angles measurement in degrees.
It's 1/2 of sin(2 theta) .
The derivative of (sin (theta))^.5 is (cos(theta))/(2sin(theta))
1 cot(theta)=cos(theta)/sin(theta) cos(45 degrees)=sqrt(2)/2 AND sin(45 degrees)=sqrt(2)/2 cot(45 deg)=cos(45 deg)/sin(deg)=(sqrt(2)/2)/(sqrt(2)/2)=1