I am assuming that the equation is y = 2.5x
You should be given a set of values of x, or a range for x.
If given a set of values, pick a value, multiply it by 2.5 and that is the corresponding y value.
If given a range, select 5 or 6 suitable values of x in the range. Again, multiply each by 2.5 and these are the corresponding y values.
Without an equality sign the given terms can't be considered to be an equation.
There can be no answer because the question contains an expression, not an equation or inequality.
The value of X in the equation -25x - 99 = 10 is 4.36.
5x - 6 = -25x = 4x = 4/5, the intercept
This is a quadratic equation in the form of: 52 - 25x + 30 = 0 Solve by using the quadratic equation formula: x = 2 or x = 3 Or by factorising: (5x-10)(x-3) = 0, which means that x = 10/5 or x = 3
Without an equality sign the given terms can't be considered to be an equation.
Without an equality sign it cannot be considered to be a straight line equation. But if you mean: y = 25x-3 then the parallel line is y = 25x-61
Substitution method: from first equation y = 5x - 8. In the second equation this gives 25x - 5(5x - 8) = 32 ie 25x - 25x + 40 = 32 ie 40 = 32 which is not possible, so the system has no solution. Multiplication method: first equation times 5 gives 25x - 5y = 40, but second equation gives 32 as the value of the identical expression. No solution.
The value of X in the equation -25x - 99 = 10 is 4.36.
There can be no answer because the question contains an expression, not an equation or inequality.
25x-32 = 7 25x-9 = 7 25x = 7+9 25x = 16 x = 16/25
3
5x - 6 = -25x = 4x = 4/5, the intercept
32 + 25x + 18 = 50 + 25x
This is a quadratic equation in the form of: 52 - 25x + 30 = 0 Solve by using the quadratic equation formula: x = 2 or x = 3 Or by factorising: (5x-10)(x-3) = 0, which means that x = 10/5 or x = 3
Simplify 5y = 25x - 15 by dividing each term by 5 to produce y = 5x - 3. By definition, the y-intercept of this equation is the value of y when x = 0, in this instance -3.
25x'2