To find the y-intercept of the equation 5y = 25x - 15, we first need to isolate y. Dividing both sides by 5 gives us y = 5x - 3. The y-intercept occurs when x = 0, so substituting x = 0 into the equation gives us y = -3. Therefore, the y-intercept of the equation is -3.
2x-5y+15=0 -5y=-2x-15 y=(2/5)x+3
If: 20x+5y = 15 Then: y = -4x+3
Get in slope intercept form. 3X + 5Y = 15 5Y = -3X + 15 Y = -3/5X + 3 -3/5 is the slope of this line and the line parallel to this line
0 = -2x + 5y - 15 -5y = -2x - 15 y = 2x/5 + 3
We cannot find out the y and x intercept for the equation 3x plus 5y equals -15 by a single equation . But , we can try a hit and trial method for the same . when x =0 y =-3. when y=0 x=-5.
5y=25x 25x=5y -5y 25x-5y=0
No solution
Substitution method: from first equation y = 5x - 8. In the second equation this gives 25x - 5(5x - 8) = 32 ie 25x - 25x + 40 = 32 ie 40 = 32 which is not possible, so the system has no solution. Multiplication method: first equation times 5 gives 25x - 5y = 40, but second equation gives 32 as the value of the identical expression. No solution.
(-5, 2)
15
18y+5y+48+15 = 270 18y+5y = 270-48-15 23y = 207 y = 9
2x-5y+15=0 -5y=-2x-15 y=(2/5)x+3
If: 20x+5y = 15 Then: y = -4x+3
no
If y equals 3, 7 - 5y would be:7 - 5(3)Simplify.7 - 15 = -8.In conclusion, 7 - 5y = -8.
3x-5y=15 The equation-5y=15-3x Subtract 3x from both sidesy=-3+.6x Divide both sides by -5
18y+48+5y+15 = 270 18y+5y = 270-48-15 23y = 207 y = 9