Suppose length = L and width = Wthen perimeter, P = 2(L + W) = 16 => L + W = 8 and so W = 8 - L
Also, area A = L*W = 12
therefore L*(8 - L) = 12 or L^2 - 8L + 12 = 0 => L = 2 or L = 6
These are conjugate solutions so (L, W) = (6, 2) centimetres.
That's 3 x 8.
Area of circle = pi*212 = 1385.44236 square cm Area of rectangle = 1385.44236 square cm Lenght of rectangle = 1385.44236/18 = 76.96902 cm Perimeter of rectangle = 2(76.96902)+2(18) = 189.93804 cm
the area of a rectangleis 100 square inches. The perimeter of the rectangle is 40 inches. A second rectangle has the same area but a different perimeter. Is the secind rectangle a square? Explain why or why not.
66
yes
If the rectangle is a square, the perimeter is 48 cm. If not, there are a lot of possibilities.
24000 sq.cm.
That's 3 x 8.
9X2
Area of circle = pi*212 = 1385.44236 square cm Area of rectangle = 1385.44236 square cm Lenght of rectangle = 1385.44236/18 = 76.96902 cm Perimeter of rectangle = 2(76.96902)+2(18) = 189.93804 cm
if one length is 9cm, the other length must be 6cm to make an area of 54cm. hence the perimeter is 9+9+6+6 = 30cm
Draw it with dimensions of (6 cm) by (3 cm).
the area of a rectangleis 100 square inches. The perimeter of the rectangle is 40 inches. A second rectangle has the same area but a different perimeter. Is the secind rectangle a square? Explain why or why not.
66
21cm3
yes
Assuming that it's a rectangle then:- Area = 42*14 = 588 square cm Perimeter = 42+42+14+14 = 112 cm