Perimeter of a rectangle is 2(l+b).Area of rectangle is 216 centimeter square.
A rectangle with a perimeter of 48 and 1 side equal to 5 would have its other sides lengths of 5, 19, 19. Such a rectangle would have an area of 95 sq/m. Your question is somewhat strange, as the "length" of a rectangle generally refers to the longer side - in this case the length would be 19 and the width 5.
L + W = P/2 = 13. 13 - 7 = 6, 6/2 = 3 which is the width, making the length 10.
if the perimeter is 46m, then side + length = 23 so we need two values, when added together are 23, with a difference of 11 6 + 17 = 23, (and have a difference of 11) therefore the length = 17m, width = 6m
Perimeter is a length, and a length cannot be the same as an area.Ignoring the units, all rectangles that have the same numerical perimeter as area are those that satisfy:2 x (length + width) = length x widthwhich can be rearranged to give:width = 2 x length/(length - 2)Meaning that given any length over 2, a width can be found to give a rectangle that meets the requirement that its numerical perimeter is the same as its numerical area. (For a length greater than 0 and less than 2, the width would be negative and not possible; similarly for a length less than 0, the length is negative and not possible. When the length is 2, the width is undefined and so not possible. When the length is 0 the width is 0 and it is not a rectangle.)At some stage as the length increases, the length will equal the width and as the length continues to increase the rectangle then given will match the previous rectangles with the length and widths swapped. This occurs when:length = 2 x length/(length - 2)⇒ length x (length - 4) = 0⇒ length = 4.So, as long as the length is greater than or equal 4 it will be the longer side - the length, by convention, is the longer side. Thus all rectangles satisfy:width = 2 x length/(length - 2)with length ≥ 4, will have the numerical value of their perimeter the same as the numerical value of their area.For example:4 cm x 4 cm: perimeter = 16 cm, area = 16 cm25 cm x 31/3 cm: perimeter = 162/3 cm, area = 162/3 cm26 cm x 3 cm: perimeter = 18 cm, area = 18 cm241/2 cm x 33/5 cm: perimeter = 161/5 cm, area = 161/5 cm2etcNote: the first example is a square which is a rectangle with all the sides the same length.
It is: 12 units in length
a rectangle has a perimeter of 72m. If the length is 20 m longer than the width find its dimensions?
i don't know what length of rectangle is 7 cm longer than the width the perimeter of the rectangle is 46 cm .what is the length of the of the rectangle ?
The perimeter of a rectangle is 2length +2 width. the width is x the length is x+4. Plug into the equation 2(x)+2 (x+4)=20 2x+2x+8=20 4x=12 x=3 The width is 3 the length is 7 (3+4) Area is length times width. 3(7)= 21. the area is 21 centimeters
Perimeter of a rectangle is 2(l+b).Area of rectangle is 216 centimeter square.
the width equals 14 cm. and the length equals 31 cm.
Assuming that this is a rectangle, you know that the length (longer side) would be 7cm, and the width (shorter side) would be 6cm. The formula for perimeter is, 2(length) + 2(width) = Perimeter Now we can plug in our numbers, 2(7cm) + 2(6cm) = 14cm + 12cm = 26cm The perimeter would be 26cm, assuming that this is a rectangle ^^
A rectangle with a perimeter of 48 and 1 side equal to 5 would have its other sides lengths of 5, 19, 19. Such a rectangle would have an area of 95 sq/m. Your question is somewhat strange, as the "length" of a rectangle generally refers to the longer side - in this case the length would be 19 and the width 5.
shorter side = 10 longer side = 19
Length is 11 and width is 7 and so 11 times 7 = 77 square cm
If the rectangle is 12 feet long and has a perimeter of 40, then the height must be 8. If it is made 6 feet longer, it will have a length of 18 and a height of 8. The new area will be 144.
a rectangle as a longer side because there's 48 inches for a rectangle but there's only 45 inches for a triangle. a rectangle as a longer side because there's 48 inches for a rectangle but there's only 45 inches for a triangle.