It is not to solve so much as to see the number of solutions and whether there is a real solution to the equation. b2 - 4(a)(c) A positive answer = two real solutions. A negative answer = no real solution ( complex solution i ) If zero as the answer there is one real solution.
ax2 + bx + c = 0 , find the value of x . b2-4ac>o x is real (2 different values will solve) b2-4ac=o -> a double root (a single real number will solve it) x=real numbers. b2-4ac<0 x= two complex number roots (either pure imaginary or a complex number with real and imaginary components)
The idea is to solve certain problems, many of which appear in real life, and which don't have whole-number solutions.
6.021023 is a single number: not an equation or inequality. You cannot solve a single number!
That depends on what the question is. A percent is just a number. You're asking "How do you solve a number?"
no duffer
x2 = -25 There exists no real number for which this is true, so we must use imaginary numbers... x = 5i
If the discriminant - the part under the radical sign in the quadratic formula - is negative, then the result is complex, it is as simple as that. You can't convert a complex number to a real number. If a particular problem requires only real-number solutions, then - if the formula gives complex numbers - you can state that there is no solution.
You solve the equation.
The square of a real number is always a real number.
You cannot "solve" a single number!
The real number in '101.7' is 101. A real number is a positive whole number.