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ax2 + bx + c = 0 , find the value of x .
b2-4ac>o x is real (2 different values will solve)
b2-4ac=o -> a double root (a single real number will solve it)
x=real numbers.
b2-4ac<0
x= two complex number roots (either pure imaginary or a complex number with real and imaginary components)
What else can I help you with?
What is the turning point in the graph of a quadratic function?
The answer depends on the form in which the quadratic function is given. If it is y = ax2 + bx + c then the x-coordinate of the turning point is -b/(2a)
Find the value of x for log5 125 equals x?
assuming that this means log5125=x, x=3.
Can someone find value of cos20cos40cos80?
cos20 x cos40 x cos80 = 0.0300 radians = 0.125 degrees (the value for radians is given to four decimal places, the value in degrees is exact)
What is The sum of maximum value of sin and minimum value of cos?
The maximum value of the sine function, (\sin(x)), is 1, while the minimum value of the cosine function, (\cos(x)), is -1. Therefore, the sum of the maximum value of sine and the minimum value of cosine is (1 + (-1) = 0).
What is an expression with one variable?
3x+2 x is a variable. A variable is a symbol (x, y, etc...) that does not have an assigned value.
If a equals positive and b equals negative and c equals zero how many solutions does a Quadratic Equation have?
Two: one is 0, the other is -b/a ax2 + bx + c = 0, but c = 0 ⇒ ax2 + bx + 0 = 0 ⇒ ax2 + bx = 0 ⇒ x(ax + b) = 0 ⇒ x = 0 or (ax + b) = 0 ⇒ x = -b/a
What is the quadractic formula?
where ax2 + bx + c = 0 x = [-b +/- √(b2 -4ac)] / 2a
How can I solve a quadratic equations for x in terms of y?
A quadratic involving x and y is usually in the form 'y = ax2 + bx + c'. This form is y in terms of x, so we must rearrange it. y = ax2 + bx + c y/a = x2 + bx/a + c/a y/a = x2 + bx/a + d + e, where c/a = d + e, e = (b/a)2 y/a - e = x2 + bx/a + d y/a -e = (x + b/a)2 √(y/a - e) = x + b/a √(y/a - e) - b/a = x
What is the formula for finding the value of x in the quadratic equation ax2 bx c0?
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. However, assuming your question to find the roots or solutions of ax2 + bx + c = 0, the answer is x = [-b ± sqrt(b2 - 4ac)]/2a b2 - 4ac is called the discriminant. If the discriminant > 0 then the quadratic equation has two distinct real roots. If the discriminant = 0 then the quadratic equation has one double root. If the discriminant < 0 then the quadratic equation has two distinct complex roots that are conjugates of one another.
How do you determine wheather a quadratic function has a maximum or minimum and how do you find it?
In theory you can go down the differentiation route but because it is a quadratic, there is a simpler solution. The general form of a quadratic equation is y = ax2 + bx + c If a > 0 then the quadratic has a minimum If a < 0 then the quadratic has a maximum [and if a = 0 it is not a quadratic!] The maximum or minimum is attained when x = -b/2a and you evaluate y = ax2 + bx + c at this value of x to find the maximum or minimum value of the quadratic.
What is a simple equation?
a = bx + c bx + (c-a) = 0 x = (a-c)/b It's simple because there is only one solution. This is a quadratic equation: ax2 + bx + c = 0 It has two solutions.
When factoring a trinomial that is in the format Ax2 plus Bx plus C the number that is represented by Bshould be viewed as the?
The coefficient of x
How do you know if a quadratic has a minimum or maximum value?
When the quadratic is written in the form: y = ax2 + bx + c then if a > 0 y has a minimum if a < 0 y has a maximum and if a = 0 y is not a quadratic but y = bx + c, and it is linear. The maximum or minimum is at x = -b/(2a)
What determines if a quadratic function has no x-intercepts?
If the quadratic function is written as ax2 + bx + c, then it has no x-intercepts if the discriminant, (b2 - 4ac), is negative.
X times x plus two times x minus eight?
A quadratic of the form Ax2 + Bx + C where A=1, B=2 and C=-8
When factoring a trinomial that is in the format ax2 plus bx c the number that is represented by B should be viewed as the?
The general form of a quadratic expression is given as ax2+bx+c where "a" cannot equal zero and "b" is the coefficient of the variable "x" and also the sum of the factors of "c" when "a" is unity. Example: x2+5x+6 = (x+2)(x+3) when factored
What type of solution do you get for quadratic equations where d 0?
ax3 + bx2 + cx x(ax2 + bx + c) you get one answer as 0.
