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ax2 + bx + c = 0 , find the value of x .
b2-4ac>o x is real (2 different values will solve)
b2-4ac=o -> a double root (a single real number will solve it)
x=real numbers.
b2-4ac<0
x= two complex number roots (either pure imaginary or a complex number with real and imaginary components)
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What is the turning point in the graph of a quadratic function?
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Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. However, assuming your question to find the roots or solutions of ax2 + bx + c = 0, the answer is x = [-b ± sqrt(b2 - 4ac)]/2a b2 - 4ac is called the discriminant. If the discriminant > 0 then the quadratic equation has two distinct real roots. If the discriminant = 0 then the quadratic equation has one double root. If the discriminant < 0 then the quadratic equation has two distinct complex roots that are conjugates of one another.
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