The volume will increase in proportion to the increase in absolute temperature.
A child takes a helium balloon on a plane from Denver (with an air pressure of 0.83 atm) on a cool day when the temperature is 20C to Boston (at sea level, with an air pressure of 1.0 atm) where the temperature is 5C. Assume that no gas escapes from the balloon during the flight. What is the volume of the balloon in Boston, relative to its size in Denver
Effusion
Avogadro's Law: Doubling the number of moles of gas doubles its volume, if temperature and pressure aren't changed.A flat tire takes up less space than an inflated tire.Lungs expand as they fill with air. Exhaling decreases the volume of the lungs.A balloon filled with helium weighs much less than an identical balloon filled with air. (Avogadro's Law implies that equal volumes contain equal numbers of molecules, when pressure and temperature are held constant. Since both balloons contain the same number of molecules, and since helium atoms have lower mass than either oxygen molecules or nitrogen molecules in air, the helium balloon is lighter.)Wet air is less dense than moist air (see the FAQ on gases for an explanation).Or simply, all in all, it's just a matter of quantity of gas. (Quantity refers to it's moles). And as the quantity increases, the volume of it's containre, increases to. :)
The water has a mass of roughly 560 grams, depending on its purity and temperature. We have no idea what the mass of the balloon is.
The ratio of temperatures must be calculated for the absolute temperatures - not temps measures on the Celsius scale. So, the temperature increases from 273.15 K to 333.15 K. 333.15/273.15 = 1.2197 Therefore, the volume will increase by a multiple of 1.2197. This answer assumes that all other factors remain unchanged. That is unlikely since the elasticity of the balloon is likely to be affected by the change in temperature.
The universal gas equation is PV = nRT (Pressure x Volume = Number of moles x Universal Gas Constant x Temperature in Kelvin/Rankin). So - if Pressure is constant, the number of moles is constant, but the temperature increases from 25C (298 K) to 125C (398K) - a 34% increase, a similar 34% increase in volume will occur.
== == According to Charles's Law, "At constant pressure, the volume of a given mass of an ideal gas increases or decreases by the same factor as its temperature (in Kelvin) increases or decreases." Therefore, if the temperature of the gas is decreased, the volume of the gas will decrease proportionally, and the balloon will contract.
Assuming pressure is constant, like you said, volume and temperature have a direct relationship. As temperature increases, volume increases; as temperature decreases, volume decreases. Setting up a algebraic direct proportion, you get approximately 3.84 liters for the balloon at 285 degrees K.
assuming the balloon is closed, the air pressure would double
Isothermal is where pressure and/or volume changes, but temperature remains constant. Pressure, Volume, and Temperature are related as: PV = nRT =NkT for an ideal gas. Here, we see that since a balloon's volume is allowed to change, its pressure remains relatively constant. Whenever there is a pressure change, it'll be offset by an equivalent change in volume, thus temperature is constant.
Increase. By the ideal gas law, PV = nRT Atmospheric pressure will stay the same so the pressure in the balloon will remain about the same. n (the amount of gas in the balloon) will stay the same R is the gas constant so it stays the same consequently if P, n, and R remain the same and T increases, V must increase too.
3.5 litre if pressure is kept constant.
volume decreases considering the pressure is constant
Assuming constant amount of gas and temperature, pressure will increase as volume decreases. Conversely, pressure will decrease as volume increases. If you squeeze on a filled balloon, the volume decreases. The pressure of the air on each square inch of the balloon increases, which causes it to eventually pop if the pressure gets too high. Assuming constant amount of gas, a temperature change will already change the volume of the gas. As temperature rises, the gas expands, causing more pressure to be exerted on the balloon. Assuming constant temperature, adding more gas also increases the volume and thus increases the pressure.
As air, or a gas, warms it becomes less dense, because its volume increases. This principle can be seen in action in a hot-air balloon. The warm air within the balloon envelope is so much less dense and therefore lighter than the surrounding air that the surrounding air pressure causes the balloon to rise. The relationship of temperature and pressure for an ideal gas is stated in Charles's law: "At constant pressure, the volume of a given mass of an ideal gas increases or decreases by the same factor as its temperature (in Kelvin) increases or decreases." Stated as a formula, V/T = k, where V is the volume, T is the temperature, and k is a constant.
The volume will increase in proportion to the increase in absolute temperature.
If a balloon is squeezed, then that means the volume is decreasing. Volume and pressure vary indirectly, which means that when one goes up, the other goes down. So when you are decreasing the volume of the balloon, the pressure inside is going up (assuming constant mass and temperature).