Effusion
Yes, assuming that the environment in which the tea is "living" stays a constant temperature. Tea will cool at a constant rate, until it reaches the temperature of the environment (but it will not get any colder than this).
The volume will increase in proportion to the increase in absolute temperature.
Increasing the dimensions of the smaller of the similar triangles (if they are not already congruent) by a suitably chosen constant factor.
It depends on what kind of balloon.
No it is not.
Diffusion
The force of the pressure put on the balloon is squeezed into smaller particles so the volume is smaller. :) From Jade Nicole White. X
Small Balloon because it is smaller the heat is compacted and closer so the smaller balloon has more heat.
An example of Charles's law in action is a balloon inflating when placed in a warm environment. As the temperature increases, the gas molecules inside the balloon gain kinetic energy and move faster, causing the volume of the balloon to expand in order to maintain a constant pressure.
When the internal pressure in a balloon falls, the balloon get smaller and less buoyant.
When an inflated balloon is exposed to cold air, provided pressure is constant, the volume will decrease. Bring the balloon back to a warmer spot, and the gas gains kinetic energy from the warm air, and the balloon will plump back up.
The air particles in the balloon compress due to the cold atmosphere in the refrigerator which causes the balloon to be smaller.
if vigorous enough to create heat the balloon will expand.
For a balloon that is sealed and not full the volume of air inside the balloon will increase as it is heated. This is not however how hot air balloons work. A hot air balloon is essentially a fixed volume when it is inflated. If the air inside the balloon is heated the air inside becomes less dense so some of the air exits the balloon via the mouth of the balloon. As the air inside the balloon cools it becomes more dense so some air is ingested via the mouth of the balloon to keep it full. With each heating and cooling cycle, the pressure inside the balloon remains constant, the volume of the balloon remains constant but there is this movement of air out of and back into the balloon. P=VT Poop
due to pressure inside the balloon, will be higher because the balloon will try to get smaller and thus the balloon will ascent due to the low density of the helium inside the balloon.
If the volume of gas in the balloon remains constant, then an increase in temperature would result in an increased gas pressure in a balloon.That result can be achieved in three ways:1). Pump more gas into the balloon.or2). Heat the balloon.or3). Surround the balloon completely with something and squish it down into a smaller volume.The volume is increased.
If the volume of gas in the balloon remains constant, then an increase in temperature would result in an increased gas pressure in a balloon.That result can be achieved in three ways:1). Pump more gas into the balloon.or2). Heat the balloon.or3). Surround the balloon completely with something and squish it down into a smaller volume.The volume is increased.