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How would you find four consecutive even integers whose sum is four?
Wiki User
∙ 14y ago
You can do this by trial-and-error. Or, give the lowest of the four consecutive integers a name, like "x". The three other integers will then be "x+2", "x+4", and "x+6". So, you have to solve the equation:
x + (x + 2) + (x + 4) + (x + 6) = 4
The answer is the lowest of the four consecutive even integers.
You can do this by trial-and-error. Or, give the lowest of the four consecutive integers a name, like "x". The three other integers will then be "x+2", "x+4", and "x+6". So, you have to solve the equation:
x + (x + 2) + (x + 4) + (x + 6) = 4
The answer is the lowest of the four consecutive even integers.
You can do this by trial-and-error. Or, give the lowest of the four consecutive integers a name, like "x". The three other integers will then be "x+2", "x+4", and "x+6". So, you have to solve the equation:
x + (x + 2) + (x + 4) + (x + 6) = 4
The answer is the lowest of the four consecutive even integers.
You can do this by trial-and-error. Or, give the lowest of the four consecutive integers a name, like "x". The three other integers will then be "x+2", "x+4", and "x+6". So, you have to solve the equation:
x + (x + 2) + (x + 4) + (x + 6) = 4
The answer is the lowest of the four consecutive even integers.
Wiki User
∙ 14y ago
Wiki User
∙ 14y agoYou can do this by trial-and-error. Or, give the lowest of the four consecutive integers a name, like "x". The three other integers will then be "x+2", "x+4", and "x+6". So, you have to solve the equation:
x + (x + 2) + (x + 4) + (x + 6) = 4
The answer is the lowest of the four consecutive even integers.
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The integers are even and are 28 and 30.
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