answersLogoWhite

0

There are none because two consecutive even integers would add up to an even number and the number given of 217 is an odd number.

User Avatar

Wiki User

8y ago

Still curious? Ask our experts.

Chat with our AI personalities

JudyJudy
Simplicity is my specialty.
Chat with Judy
ProfessorProfessor
I will give you the most educated answer.
Chat with Professor
LaoLao
The path is yours to walk; I am only here to hold up a mirror.
Chat with Lao

Add your answer:

Earn +20 pts
Q: What are two consecutive even integers whose some is 217?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Continue Learning about Math & Arithmetic

What 2 consecutive integers have a some of negative 105?

The numbers are -53 and -52.


What is the link between the product of any four consecutive positive integers and some square numbers?

The product of four consecutive integers is always one less than a perfect square. The product of four consecutive integers starting with n will be one less than the square of n2 + 3n + 1


What is the consecutive integers that the square root falls between if you are looking for the square root of 14?

Try it out! Calculate the squares of some small integers! That shouldn't take too long.


If the sum of three consecutive even integers is 54 what are the integers?

Call the numbers 2n, 2n+2, and 2n+4 for some integer n. Using the form 2n ensures the numbers are even and adding 2 to the first one to get the second and then adding 2 to the third one to get the third ensures they are consecutive. Their sum is 54 so 6n+6=54 -> 6n=48 and n=8 The numbers are: 16, 18, and 20


What is the number of non-square numbers between 2 consecutive numbers?

There is no such thing as consecutive numbers because numbers are infinitely dense. Between any two numbers there is another and so there is no such thing as a "next" number.There are no integers (square or non-square) between any two consecutive integers. There are infinitely many numbers between any two consecutive integers and, if the integers are non-negative, every one of these will be a square of some number so the answer is none. If the integers are negative then the infinitely many numbers will have a square root in the complex field but not in real numbers. In this case the answer is either none or infinitely many, depending on the domain.