27 + 28 + 29 + 30 = 114
Three consecutive integers whose sum is 117 are 38, 39, and 40. N + (N+1) + (N+2) = 117 3N + 3 = 117 3N = 114 N = 38
Let the integers be x, (x+1) and (x+2) Since, x+(x+1)+(x+2) = -114, by solving the equation for x, we get that, x = -37 Hence the integers are -37, -36 and -35
The first ten consecutive composite positive integers are: 114 115 116 117 118 119 120 121 122 123
114 through 126 are all composite.
27 + 28 + 29 + 30 = 114
The consecutive odd integers for 114 are 37, 38 and 39.
117
The integers are 27, 28, 29 and 30.
27+28+29+30=114
27 28 29 30
The numbers are 56 and 58.
The numbers are 27, 28, 29 and 30.
The larger is 114, and the other is 112.
27 + 28 + 29 + 30 = 114
Three consecutive integers whose sum is 117 are 38, 39, and 40. N + (N+1) + (N+2) = 117 3N + 3 = 117 3N = 114 N = 38
The integers are 37, 38 and 39.