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There is no such set of integers.

Q: 4 consecutive even integers whose sum is -114?

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27 + 28 + 29 + 30 = 114

Three consecutive integers whose sum is 117 are 38, 39, and 40. N + (N+1) + (N+2) = 117 3N + 3 = 117 3N = 114 N = 38

The integers are 37, 38 and 39.

Since the average of the three integers will be 114/3 = 38, and the three numbers are consecutive, the numbers will be 36, 38 and 40. Another way to do this problem using algebra is to let the first integer be n, then the next two are n+2 and n+4. Their sum is 3n+6 and it equals 114 So 3n+6=114 and 3n=108 so n=36 then next two numbers must be 38 and 40 since they are consecutive even integers.

27, 28, 29 and 30

Related questions

The consecutive odd integers for 114 are 37, 38 and 39.

27 + 28 + 29 + 30 = 114

117

The integers are 27, 28, 29 and 30.

27+28+29+30=114

27 28 29 30

The numbers are 56 and 58.

The numbers are 27, 28, 29 and 30.

The larger is 114, and the other is 112.

Three consecutive integers whose sum is 117 are 38, 39, and 40. N + (N+1) + (N+2) = 117 3N + 3 = 117 3N = 114 N = 38

27 + 28 + 29 + 30 = 114

The integers are 37, 38 and 39.