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Q: 4 consecutive even integers whose sum is -114?

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27 + 28 + 29 + 30 = 114

Three consecutive integers whose sum is 117 are 38, 39, and 40. N + (N+1) + (N+2) = 117 3N + 3 = 117 3N = 114 N = 38

Let the integers be x, (x+1) and (x+2) Since, x+(x+1)+(x+2) = -114, by solving the equation for x, we get that, x = -37 Hence the integers are -37, -36 and -35

The first ten consecutive composite positive integers are: 114 115 116 117 118 119 120 121 122 123

114 through 126 are all composite.

Related questions

27 + 28 + 29 + 30 = 114

The consecutive odd integers for 114 are 37, 38 and 39.

117

The integers are 27, 28, 29 and 30.

27+28+29+30=114

27 28 29 30

The numbers are 56 and 58.

The numbers are 27, 28, 29 and 30.

The larger is 114, and the other is 112.

27 + 28 + 29 + 30 = 114

Three consecutive integers whose sum is 117 are 38, 39, and 40. N + (N+1) + (N+2) = 117 3N + 3 = 117 3N = 114 N = 38

The integers are 37, 38 and 39.

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