Here are two ways:
You could make a table:
. |H | T
---------
H| 1 0
T| 0 0
The row across the top is the first toss. The column is the second toss. The one with both Heads is indicated with a 1. There is 1 chance out of the 4 possible outcomes, so 1/4 = 0.25
Mathematically: Chance of first coin Heads = 0.5, chance of 2nd coin heads = 0.5; then multiply the two probabilities together, since they both have to happen: (0.5)*(0.5) = 0.25
0.63 = 0.216
It is 1/2.
The number of total outcomes on 3 tosses for a coin is 2 3, or 8. Since only 1 outcome is H, H, H, the probability of heads on three consecutive tosses of a coin is 1/8.
3 out of 8
If you know that two of the four are already heads, then all you need to find isthe probability of exactly one heads in the last two flips.Number of possible outcomes of one flip of one coin = 2Number of possible outcomes in two flips = 4Number of the four outcomes that include a single heads = 2.Probability of a single heads in the last two flips = 2/4 = 50%.
0.63 = 0.216
The probability of heads is 0.6 and that of tails is 0.4. Since the probabilities are not 0.5, it is a biased coin. That is the answer!
colors cards dice coin heads tails
Experimental probability is calculated by taking the data produced from a performed experiment and calculating probability from that data. An example would be flipping a coin. The theoretical probability of landing on heads is 50%, .5 or 1/2, as is the theoretical probability of landing on tails. If during an experiment, however, a coin is flipped 100 times and lands on heads 60 times and tails 40 times, the experimental probability for this experiment for landing on heads is 60%, .6 or 6/10. The experimental probability of landing on tails would be 40%, .4, or 6/10.
It is 1/2.
The number of total outcomes on 3 tosses for a coin is 2 3, or 8. Since only 1 outcome is H, H, H, the probability of heads on three consecutive tosses of a coin is 1/8.
3 out of 8
Since a coin has two sides and it was tossed 5 times, there are 32 possible combinations of results. The probability of getting heads three times in 5 tries is 10/32. This is 5/16.
If you know that two of the four are already heads, then all you need to find isthe probability of exactly one heads in the last two flips.Number of possible outcomes of one flip of one coin = 2Number of possible outcomes in two flips = 4Number of the four outcomes that include a single heads = 2.Probability of a single heads in the last two flips = 2/4 = 50%.
With one toss of a coin, there can be at most 1 head. So the probability of 4 or more heads is very definitely 0.
The probability is 0.5
When the event of interest is a cumulative event. For example, to find the probability of getting three Heads in 8 tosses of a fair coin you would use the regular binomial distribution. But to find the probability of up to 3 Heads you would use the cumulative distribution. This is because Prob("up to 3") = Prob(0 or 1 or 2 or 3) = Prob(0) + Prob(1) + Prob(2) + Prob(3) since these are mutually exclusive.