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Here are two ways:

You could make a table:

. |H | T

---------

H| 1 0

T| 0 0

The row across the top is the first toss. The column is the second toss. The one with both Heads is indicated with a 1. There is 1 chance out of the 4 possible outcomes, so 1/4 = 0.25

Mathematically: Chance of first coin Heads = 0.5, chance of 2nd coin heads = 0.5; then multiply the two probabilities together, since they both have to happen: (0.5)*(0.5) = 0.25

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Q: How would you find the probability that you would toss two heads in a row with a coin?
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