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How would you find the vertex of the parabola 1 plus 12x -6x squared?
Wiki User
∙ 6y ago
Parabola: 1+12x-6x^2
Factorizing: -6(x^2 -2x -1/6)
Completing the square: -6((x-1)^2 -1 -1/6) => -6(x-1)^2 +7
Vertex of parabola is at: (1, 7)
Wiki User
∙ 6y ago
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To find the value of a in a parabola opening up or down, subtract the y-value of the parabola at the vertex from the y-value of the point on the parabola that is one unit to the of the vertex?
right
To find the value of a in a parabola opening left or right subtract the x value of the parabola at the vertex from the x value of the point on the parabola that is one unit the vertex?
Above
How do you find the vertex of the parabola y equals -4x2 - 16x - 11?
You would convert it to vertex form by completing the square. You can also find the optimum value as optimum value and vertex are the same.
How do you sketch graphs and write equations for parabolas?
If you want to sketch graphs you have to observe the parabola first then find the vertex afterwards you connect them and you've arrived at your answer. In order to write equations for parabolas it has to have x square in it. The standard equation for a parabola is (y - k)2 = 4a(x - h) where h and k are the x- and y-coordinates of the vertex of the parabola and 'a' is a non zero real number. This website at the related link should help, for the equation at least. A parabola is a basic U shaped graph that meets at one point called a vertex. The equation for Andy parabola must have a number being squared such as x2.
What does calculate the vertex mean in math terms?
Most likely you have an equation of a parabola. The vertex of a parabola is the location where it changes from going down, to going up (a simplified explanation). Most parabolas that we think of are oriented up or down (the axis is parallel to the y axis), but they could be oriented sideways, or even at an angle. To calculate the vertex of a parabola ususally means to find the coordinates of the vertex.
To find the value of a in a parabola opening up or down subtract the y-value of the parabola at the vertex from the y-value of the point on the parabola that is one unit to the of the vertex?
To find the value of a in a parabola opening up or down subtract the y-value of the parabola at the vertex from the y-value of the point on the parabola that is one unit to the right of the vertex.
To find the value of a in a parabola opening up or down, subtract the y-value of the parabola at the vertex from the y-value of the point on the parabola that is one unit to the of the vertex?
right
To find the value of a in a parabola opening left or right subtract the x value of the parabola at the vertex from the x value of the point on the parabola that is one unit the vertex?
Above
How do you find the vertex of the parabola y equals -4x2 - 16x - 11?
You would convert it to vertex form by completing the square. You can also find the optimum value as optimum value and vertex are the same.
What is the vertex for the parabola y equals x squared plus 4x plus 5?
The vertex of a parabola is the minimum or maximum value of the parabola. To find the maximum/minimum of a parabola complete the square: x² + 4x + 5 = x² + 4x + 4 - 4 + 5 = (x² + 4x + 4) + (-4 + 5) = (x + 2)² + 1 As (x + 2)² is greater than or equal to 0, the minimum value (vertex) occurs when this is zero, ie (x + 2)² = 0 → x + 2 = 0 → x = -2 As (x + 2)² = 0, the minimum value is 0 + 1 = 1. Thus the vertex of the parabola is at (-2, 1).
How do you find the vertex of the parabola 3x squared -x plus 4?
7
How do you sketch graphs and write equations for parabolas?
If you want to sketch graphs you have to observe the parabola first then find the vertex afterwards you connect them and you've arrived at your answer. In order to write equations for parabolas it has to have x square in it. The standard equation for a parabola is (y - k)2 = 4a(x - h) where h and k are the x- and y-coordinates of the vertex of the parabola and 'a' is a non zero real number. This website at the related link should help, for the equation at least. A parabola is a basic U shaped graph that meets at one point called a vertex. The equation for Andy parabola must have a number being squared such as x2.
What does calculate the vertex mean in math terms?
Most likely you have an equation of a parabola. The vertex of a parabola is the location where it changes from going down, to going up (a simplified explanation). Most parabolas that we think of are oriented up or down (the axis is parallel to the y axis), but they could be oriented sideways, or even at an angle. To calculate the vertex of a parabola ususally means to find the coordinates of the vertex.
How do you find the axis of symmetry and vertex of y equals x squared plus 6x plus 10?
By completing the square y = (x+3)2+1 Axis of symmetry and vertex: x = -3 and (-3, 1) Note that the parabola has no x intercepts because the discriminant is less than zero
An equilateral triangle is inscribed in a parabola with its vertex at the vertex of the parabola how do you find the length of the equilateral triangle?
First you need more details about the parabola. Then - if the parabola opens upward - you can assume that the lowest point of the triangle is at the vertex; write an equation for each of the lines in the equilateral triangle. These lines will slope upwards (or downwards) at an angle of 60°; you must convert that to a slope (using the tangent function). Once you have the equation of the lines and the parabola, solve them simultaneously to check at what points they cross. Finally you can use the Pythagorean Theorem to calculate the length.
How would you find the vertex p value focus directrix and focal width of negative one fourth x squared equals y?
-(1/4) x2 = y . . . putting this in the standard form x2 = 4cy it becomes : x2 = 4*(-1)y = -4y. This tells us that the parabola is a downward opening parabola with its vertex at the origin(0.0). The focus is at a distance of -1 from the vertex, that is (0,-1). The directrix is equidistant to the focus but on the opposite side of the vertex and is thus the line y = 1. The length of the chord passing through the focus and perpendicular to the major axis is called the Latus Rectum and has a length of 4c. As c = -1 then the length is 4 but again shows as a negative value as it is "below" the vertex.
Find the vertex of the parabola y equals -2x2 plus 12x - 13?
The points at which the parabola intersects the x axis are 3-sqrt(10)/2 and 3+sqrt(10)/2. The X position of the vertex is in the middle, at 3. The y position, from there, is simply found by substituting 2 for x in the equation. As a result, the vertex is at (3, 5).
