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The points at which the parabola intersects the x axis are 3-sqrt(10)/2 and 3+sqrt(10)/2. The X position of the vertex is in the middle, at 3. The y position, from there, is simply found by substituting 2 for x in the equation. As a result, the vertex is at (3, 5).
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What is the vertex of the parabola y equals x2 plus 8x plus 5?
The vertex has a minimum value of (-4, -11)
What is the vertex of the parabola y equals 2x squared plus 12x 13?
(-3, -5)
What is the vertex form of y equals x2 plus 4x - 7?
The vertex of the positive parabola turns at point (-2, -11)
How does y equals 4x2 plus 21x look in a graph?
It is a parabola with its vertex at the origin and the arms going upwards.
What is the y value of the maximum y equals -x2 plus 6x-7?
20 and the vertex of the parabola is at (3, 20)
What is the vertex of the parabola y equals x2 plus 8x plus 5?
The vertex has a minimum value of (-4, -11)
What is the vertex of the parabola y equals 2x squared plus 12x 13?
(-3, -5)
What is the vertex form of y equals x2 plus 4x - 7?
The vertex of the positive parabola turns at point (-2, -11)
How does y equals 4x2 plus 21x look in a graph?
It is a parabola with its vertex at the origin and the arms going upwards.
What is the vertex of the parabola when y equals 3x squared plus 2x minus 1?
The minimum value of the parabola is at the point (-1/3, -4/3)
What is the y value of the maximum y equals -x2 plus 6x-7?
20 and the vertex of the parabola is at (3, 20)
What is the vertex for the parabola y equals x squared plus 4x plus 5?
The vertex of a parabola is the minimum or maximum value of the parabola. To find the maximum/minimum of a parabola complete the square: x² + 4x + 5 = x² + 4x + 4 - 4 + 5 = (x² + 4x + 4) + (-4 + 5) = (x + 2)² + 1 As (x + 2)² is greater than or equal to 0, the minimum value (vertex) occurs when this is zero, ie (x + 2)² = 0 → x + 2 = 0 → x = -2 As (x + 2)² = 0, the minimum value is 0 + 1 = 1. Thus the vertex of the parabola is at (-2, 1).
What is y equals x2 plus 2x plus 1 on a graph?
Interpreting that function as y=x2+2x+1, the graph of this function would be a parabola that opens upward. It would be equivalent to y=(x+1)2. Its vertex would be at (-1,0) and this vertex would be the parabola's only zero.
What is the x coordinate of the vertex parabola defined by the following function 3x plus x plus 7x plus 4?
The given equation is not that of a parabola.
How do you find the axis of symmetry and vertex of y equals x squared plus 6x plus 10?
By completing the square y = (x+3)2+1 Axis of symmetry and vertex: x = -3 and (-3, 1) Note that the parabola has no x intercepts because the discriminant is less than zero
Find the vertex of y equals x2 plus 10x plus 22?
-2-5
Vertex for y equals x2 plus 2x plus 1?
The vertex is at (-1,0).
