This would be the same as asking how many times does nine go into 1000, since every integer divisible by 9 is just every ninth number, so you divide by 9 and then truncate, since the fractional portion does not represent getting to another integer, yet. 1000/9 = 111.11111...., so the answer is 111.
There is no such thing as "solving integers". You can solve an equation, which means finding all the unknowns in that equation, but you can't solve an integer.
There are three consecutive integers. Let's call the middle one x. The one before it is x - 1 and the one after it is x + 1. Adding them together equals 3x. That means that whatever they equal has to be a multiple of 3. Since 176 is not divisible by 3, you will not be able to find three consecutive integers with that total.
9 of them.
im not 100 percent sure but i thing its: (x+1)+(x+2)+(x+3)=96
A basic logarithmic equation would be of the form y = a + b*ln(x)
finding the mean of the integers of -5,0,2,3
You find the equation of a graph by finding an equation with a graph.
Multiplication
finding the soultion or answer .
good luck finding
The product of two integers is found by multiplying them. Eg. the product of 5 and 3 is 15.
The chances of you finding a number divisible by 4 is 1/4 (because out of every four numbers, 1 of them is divisible by 4), and a 1/3 chance of finding a number divisible by 3 (see above). If we add them up, we get the chance, 1/4+1/3= 3/12+4/12. Now this would be saying that finding numbers that would be divisible by 12 (the ones divisible by 3 AND 4) would count twice, and we don't want that. To counter this, we have to subtract the chances of you finding a multiple of 12 once (so that the chances of finding the multiple of 12 would count ONCE). This translates to 3/12+4/12-1/12=6/12=1/2. :)