If you the radius of the circle is r then the perimeter of a quadrant = r*(2 + pi/2).
perimeter of what quadrant?
If you the radius of the circle is r then the perimeter of a quadrant = r*(2 + pi/2).
It is the sum of its 4 sides which is its perimeter.
In a circle of radius, r, perimeter of quadrant = pi*r/2 + 2r = r*(pi/2 + 2)
that would be a squere xD
Area of a quadrant = 0.5x(side A + opposite side B)x0.5x(side C + opposite side D) Area of a quadrant = 0.5x(side A + opposite side B)x0.5x(side C + opposite side D)
Pi / 5 would be in Quadrant I.
If you know the perimeter, there is no need to find it again.
It is not possible. A quadrant extends infinitely far in two directions and so has no centre.
To find the perimeter you add and to find the area we multiply.
If the radius of the circle is r, then the area of the quadrant is 0.25*pi*r^2
If A is in quadrant IV, then A/2 is in quadrant II. Yes, the fact than cos(A) is 0.1 means that A is in quadrant I or IV, but it really is not required in order to answer the question. It is superfluous.