No. 100 is only divisible by 5 and these other numbers: 1, 2, 4, 10, 20, 25, 50, 100.
The numbers that are divisible by both 3 and 5 have to be a factor of 15. That leaves 15, 30, 45, 60, 75, and 90. There are 6 numbers less than 100 divisible by 3 and 5
100
105
150
87 is divisible by 1, 3, 29, and 87. 100 is divisible by 1, 2, 4, 5, 10, 20, 25, 50, and 100, therefore the only number divisible by 87 and 100 is 1.
150
An integer that is divisible by 100 with a remainder. The answer should be a whole number as well.eg. 3/100 = 0.03therefore 3 is not evenly divisible by 100300/100 = 3therefore 300 is evenly divisible by 100
2390 is not divisible by 3 but is divisible by 5. 2 + 3 + 9 + 0 = 14; 1 + 4 = 5: 5 is not divisible by 3, so 14 is not divisible by 3, so 2390 is not divisible by 3. 2390 ends with a 0, so 2390 is divisible by 5.
2 times 3 times 5 is 30 so you just have to have a number divisible by 30 so 120.
A number that is divisible by 15 is divisible both by 5 and 3 A number is divisible by 5 if it ends with 0 or 5 A number is divisible by 3 if the sum of its digits is divisible by 3 e.g. 4035 is divisible by 15 as it ends with a 5 and 4+0+3+5=12 which is divisible by 3
There are 27 such numbers.
100 90 76 5 4 3 and 2