A number that is divisible by 15 is divisible both by 5 and 3 A number is divisible by 5 if it ends with 0 or 5 A number is divisible by 3 if the sum of its digits is divisible by 3 e.g. 4035 is divisible by 15 as it ends with a 5 and 4+0+3+5=12 which is divisible by 3
It is divisible by 2 and 3. It isn't divisible by 5 and 10.
Is 5225 divisible by 3? A number is divisible by 3, if the sum of its digits is evenly divisible by 3. 5 + 2 + 2 + 5 = 14. Since 14 is not divisible by 3, neither is 5225.
a number that is divisible by 3 and 5 but not by 4= 15
As 235 is ending by a 5 then it is divisible by 5 As 235 is not even it is not divisible by 2 As 2+3+5 is not divisible by 3, 235 is not divisible by 3 235/5 = 47 47 is prime so 235 = 5 * 47 and there's no other way to factorize it
2, 5, 10, 239, 478, 1195.
A number that is divisible by 15 is divisible both by 5 and 3 A number is divisible by 5 if it ends with 0 or 5 A number is divisible by 3 if the sum of its digits is divisible by 3 e.g. 4035 is divisible by 15 as it ends with a 5 and 4+0+3+5=12 which is divisible by 3
It is divisible by 2 & 3. It is not divisible by 5, 9 & 10. 534 is even → divisible by 2 5 + 3 + 4 = 12 → divisible by 3 534 does not end in 0 or 5 → not divisible by 5 5 + 3 + 4 = 12 → not divisible by 9 534 does not end in 0 → not divisible by 10
15 is divisible by 3 and 5.
it's not divisible by neither 5 or 3
yep it is because 2 is divisible by 2 and 3 is divisible by 3 and 0 is divisible by 5 have fun suckers!
It is divisible by 2 and 3. It isn't divisible by 5 and 10.
Is 5225 divisible by 3? A number is divisible by 3, if the sum of its digits is evenly divisible by 3. 5 + 2 + 2 + 5 = 14. Since 14 is not divisible by 3, neither is 5225.
Well, let's take a moment to look at this question. To see if a number is divisible by 3, you can add up the digits and see if that sum is divisible by 3. For 780, 7 + 8 + 0 = 15, which is divisible by 3. But for 320, 3 + 2 + 0 = 5, which is not divisible by 3. So, 780 is divisible by 3. Now, to check if a number is divisible by 5, you can see if the last digit is 0 or 5. In this case, 780 ends in 0, so it's divisible by 5. However, 320 does not end in 0 or 5, so it's not divisible by 5. So, 780 is divisible by both 3 and 5, while 320 is only divisible by 5.
No, look at 5 it is odd and not divisible by 3. false,because if you look at the 5 it is not divisible by 3.
Oh, dude, let's break it down. So, to see if 302 is divisible by 3, you gotta add up the digits: 3 + 0 + 2 = 5. And guess what? 5 is definitely not divisible by 3, so the answer is a big fat nope! Like, 302 is not playing nice with the number 3.
No. divisible by 3 4 5 is 60