a = 3/sqrt(2)*i + 3/sqrt(2)*j
b = 5j
a.b = |a|*|b|*cos(q)
= 3*5*cos(45) = 15/sqrt(2)
any length between 1.5 and 8.5 meters depending on the angle between the vectors. find the dot product of the two vectors to find the magnitude. e.g. two vectors a x b . y c z gives a.x+b.y+c.z= your final answer. The dots mean times by (btw)
take a protractor and line up the origin of the angle with the dot. then folow th line up to the corresponding numbe, which is the angle
<ab> = |a|*|b|*cos(x) where |a| is the length of the vector a, |b| is the length of the vector b, and x is the angle between them.
Normally, you should be able to use a protractor ( a half circle shaped piece that has a lot of marks around the curved part.) Find the vertex of the angle (the spot two lines come together) On the flat pat of the protractor, there should be a dot in the middle. Put the vertex there. Now, line one of the lines up with the bottom of the angle, making sure you keep the dot on the vertex. Next, find the other line. follow it up to the curved part. There will be marks there that have numbers on them; find the one that matches up with your line. Those marks have marks, which are the degrees, or measures, of the angle. Now, you know the measure of your angle.
Your question is kind of confusing, but if you're asking what the angle between two unit vectors A and B is, then the answer is: the inverse cosine of the dot products of A and B.
using the "dot product" formula, you can find the angle. where |a| denotes the length (magnitude) of a. More generally, if b is another vector : where |a| and |b| denote the length of a and b and θis the angle between them. Thus, given two vectors, the angle between them can be found by rearranging the above formula: : :
it is the dot product of displacement and force . i.e. Fdcos(A) where F is the magnitude of force , d is the magnitude of displacement and A is the angle between them
take a protractor and line up the origin of the angle with the dot. then folow th line up to the corresponding numbe, which is the angle
any length between 1.5 and 8.5 meters depending on the angle between the vectors. find the dot product of the two vectors to find the magnitude. e.g. two vectors a x b . y c z gives a.x+b.y+c.z= your final answer. The dots mean times by (btw)
To find the angle between two vectors, you need to use this form: a ∙ b / (|ab|) = cos(θ) θ = arccos(a ∙ b / (|ab|)) where a and b are vectors. Compute the dot product and the norm of |a| and |b|. Then, compute the angle between the vectors.
That fact alone doesn't tell you much about the original two vectors. It only says that (magnitude of vector-#1) times (magnitude of vector-#2) times (cosine of the angle between them) = 1. You still don't know the magnitude of either vector, or the angle between them.
Use a protractor, or computer software such as GeoGebra (available for free).To draw an an angle of specified measure with a protractor:Draw a straight linePlace a dot at one end of the line. The dot represents the vertex of the angle.Place the center of the protractor at the vertex dot and the baseline of the protractor along line you drew (an arm of the angle).Find the required angle on the scale and then mark a small dot at the edge of the protractor.Join the small dot to the vertex with a ruler to form the second arm of the angle.Label the angle with capital letters.
Perpendicular means that the angle between the two vectors is 90 degrees - a right angle. If you have the vectors as components, just take the dot product - if the dot product is zero, that means either that the vectors are perpendicular, or that one of the vectors has a magnitude of zero.
You can find them at any store that sell's CD's for the most part.
<ab> = |a|*|b|*cos(x) where |a| is the length of the vector a, |b| is the length of the vector b, and x is the angle between them.
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