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Perimeter = 2 x (length + width), area = Length x width. Perimeter is not directly related to area except in the cases of circles and squares.

Consider a rectangle of 60 sq cm: the integer possibilities for length and width are numerous: 1 x 60, 2 x 30, 3 x 20, 4 x 15, 5 x 12 and 6 x 10.

The respective perimeters are 122 cm, 100 cm, 46 cm, 38 cm, 34 cm and 32 cm.

Note that the nearer the shape becomes to a square, the smaller the perimeter. (A square would have a perimeter of a whisker under 31 cm.)

Q: If 2 different rectangles have the same perimeter why is the area different for each?

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area = 144 square units perimeter = 48 units

The perimeter is the outside of a shape and the area is the inside of it

It is different for each shape. A perimeter is the distance around an object and the area is the square units it takes up.

3*27 = 81 and 3+3+27+27 = a perimeter of 60 inches

Depends what you are drawing on.

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area = 144 square units perimeter = 48 units

Not necessarily. Let's say that there is a circle with the area of 10. Now there is a star with the area of 10. They do not have the same perimeter, do they? That still applies with rectangles. There might be a very long skinny rectangle and a square next to each other with the same area, but that does not mean that they have the same perimeter. Now if the rectangles are congruent then yes.

The perimeter is the outside of a shape and the area is the inside of it

You can't tell the area from knowing the perimeter. There are an infinite number of different rectangles, all with the same perimeter, that all have different areas. Here are a few rectangles that all have perimeters of 42. The last number after each one is its area: 1 cm by 20 cm . . . . . 20 square centimeters 2 x 19 . . . . . 38 3 x 18 . . . . . 54 4 x 17 . . . . . 68 5 x 16 . . . . . 80 10 x 11 . . . 110

It is different for each shape. A perimeter is the distance around an object and the area is the square units it takes up.

* It is unclear if the question is asking about two rectangles, each with a perimeter of 16, or two rectangles whose perimeters sum to 16. This answer assumes the former.Other than the 4x4 square, which coincidentally has both a perimeter and area of 16, some examples would be:1 x 7 rectangle : perimeter 16 in. , area 7 sq. in2 x 6 rectangle : perimeter 16 in., area 12 sq. in3 x 5 rectangle: perimeter 16 in., area 15 sq. inYou can calculate that for a given perimeter, the largest area is found in the square with a side measurement of P/4, i.e. the length and the width are the same.

3*27 = 81 and 3+3+27+27 = a perimeter of 60 inches

Depends what you are drawing on.

The answers depend on what measures are available for the rectangles (sides, diagonals), for the triangle (3 sides, 2 sides and included angle, one side and 2 angles), and for the circle (radius, perimeter). In each case the formula to be used will be different.

4.5*18 = 81 and 4.5+4.5+18+18 = a perimeter of 45 inches 3*27 = 81 and 3+3+27+27 = a perimeter of 60 inches

An infinite amount. You need to specify down to what decimal point. I.e. 4+3.5+4+3.5 = 15, area = 14cm^2. 4.000001+3.499999+4.000001+3.499999=15, area = 13.9999995cm^2

Perimeter=find each perimeter of each side of the box then add them all up area=find each are of each side of the box then add them all up