area = 144 square units perimeter = 48 units
12
i am doing my homework right now and I am stuck on that problem
Yes: P = 2(L + W) which is 32 in each example.
3*27 = 81 and 3+3+27+27 = a perimeter of 60 inches
area = 144 square units perimeter = 48 units
12
Not necessarily. Let's say that there is a circle with the area of 10. Now there is a star with the area of 10. They do not have the same perimeter, do they? That still applies with rectangles. There might be a very long skinny rectangle and a square next to each other with the same area, but that does not mean that they have the same perimeter. Now if the rectangles are congruent then yes.
180
i am doing my homework right now and I am stuck on that problem
no because one rectangle may be 3x4 which the perimeter is 14 and one rectangle may be 5x2 which as well equals 14
Yes, all rectangles can be considered parallelograms since they have opposite sides that are parallel to each other.
Yes: P = 2(L + W) which is 32 in each example.
3*27 = 81 and 3+3+27+27 = a perimeter of 60 inches
4.5*18 = 81 and 4.5+4.5+18+18 = a perimeter of 45 inches 3*27 = 81 and 3+3+27+27 = a perimeter of 60 inches
Yes, because 12 + 4 = 16 = 13 + 3 and in each case, the perimeter is 2*(L + B) = 32 metres.
* It is unclear if the question is asking about two rectangles, each with a perimeter of 16, or two rectangles whose perimeters sum to 16. This answer assumes the former.Other than the 4x4 square, which coincidentally has both a perimeter and area of 16, some examples would be:1 x 7 rectangle : perimeter 16 in. , area 7 sq. in2 x 6 rectangle : perimeter 16 in., area 12 sq. in3 x 5 rectangle: perimeter 16 in., area 15 sq. inYou can calculate that for a given perimeter, the largest area is found in the square with a side measurement of P/4, i.e. the length and the width are the same.