If a and b are both rational then a = 0 = b.
If they are not both rational then there are an infinite number of solutions.
2a + 1 = 3subtract 1 from both sides2a = 2divide both sides by 2a = 1
2a + 2b = c subtract 2a from both sides 2a - 2a + 2b = c - 2a 2b = c - 2a divide both sides by 2 (2/2)b = (c - 2a)/2 b = (c - 2a)/2 --------------------
To solve this, isolate x. first, add 10 to both sides. this will leave you with 2a + 15 = a Then, subtract 2a from both sides. This will leave you with 15 = -a Therefore, -15 = a
a + a + a - 2a = 3a - 2a = a
5a - 5 = 7 + 2a ( subtract 2a from both sides) 3a - 5 = 7 (add 5 to both sides) 3a = 12 ( divide both sides by 3) a = 4
2a x 3 = 24= 6a = 24(divide both sides by 6)a = 4
Since you have A on both sides of the equation, 2A = 24A, A must be 0, though it is more likely that you're missing a term from one side of the equation.
6a+1=2a+25 Subtract 2a from both sides 4a+1=25 Subtract 1 from both sides 4a=24 Divide both sides by 4 a=6 That is your final answer.
a = 26
6
4
2a = 35 a = 35/2 a = 17.5