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3x-1 = 11 3x = 11+1 3x = 12 x = 4 Therefore: x2+2 = 18
- If 3X - 1 = 11, what is the value of X^2 + X?
3x-1 = 11 3x = 11+1 = 12 x = 12/3 = 4 Therefore: x2 + 2 = 16 + 2 = 18
x=-11
If 3x - 1 = 11: To solve this equation, add 1 to each side of the equation to isolate x (3x -1 +1 = 11 + 1) and now the equation is 3x = 12. The next step is to divide both sides of the equation by 3 to find the value of x (3x / 3 = 12 / 3) for the answer x = 4. Not sure what you mean by x2 x, but you can substitute the value of x (which is 4) to solve.
3x-1=11 solves to x=4. Plug in 4 to get 42+4. The answer is 20.
3x-1=11 3x = 12 x = 4 Then, x^2 +x = 20.
3x - 2 = 11 3x = 13 x = 13/3 x2 + x = x( x + 1 ) = (13/3) (16/3) = 208/3 = 69-1/3
The answer would be 3x if 'X2' is '2x', but if 'X2' is x2, then the total answer would be x2 + x.
3x-1=11 (3x-1)+1=11+1 3x=12 (3x)x(1/3)=12 x (1/3) x=4 x^2+4 16+4 =20
First take out -3x to make-3x(x2+11)If you're not using imaginary numbers, then you're done. Otherwise factor x2+11 using the sum of two squares rule.-3x(x-sqrt(11)i)(x+sqrt(11)i)
3x - 1 = 11 so 3x = 12 so x = 4, so x^2 + x = 16 + 4 = 20 3x=12 so therefore x=4 x2 + x = 16 + 4 = 20